Answer:
0.4cm
Explanation:
First, you calculate the dis acceleration of the electron generated by the potential difference between the plates:
(1)
q: charge of the electron = 1.6*10^-19 C
V: potential difference between plates = 100V
m: mass of the electron
d: distance between parallel plates = 1cm = 0.01m
by replacing the values of the parameters you obtain:
you use this value in the following kinematic equation:
(2)
v: final velocity = 0m/s (until the electron stops)
from the equation (2) you calculate x, the distance traveled by the electron. But before you calculate the initial velocity of the electron by using the following equation:
Next, you replace vo in (2) to obtain x:
Then, the electron travels 0.1cm from the middle of the region between the parallel plates, hence, the distance between the electron and the negatve plate is:
0.5cm-0.1cm=0.4cm
There is no relationship whatsoever.
Answer:
20 MHz
Explanation:
Since speed of radio waves = speed of light = c and for a wave, v = fλ where v = speed of wave, f = frequency and λ = wavelength.
Given that λ = 15 m and v = c = 3 × 10⁸ m/s
f = v/λ
substituting the values of the variables into the equation, we have
f = v/λ = 3 × 10⁸ m/s ÷ 15 m
= 0.2 × 10⁸ Hz
= 2 × 10⁷ Hz
= 20 × 10⁶ Hz
= 20 MHz
mass = 30kg
frictional force = coefficient of friction * (mass * g)
g = 9.8 m/s^2
So:
60N = x * 294 N
x = 60 N / 294 N = 0,2
Answer: The answer is letter H