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3 years ago

12

A 30 kg object has a frictional force of 60 N. It's coefficient of friction must be...?

1 answer:

MrRa [10]3 years ago

3 0

mass = 30kg

frictional force = coefficient of friction * (mass * g)

g = 9.8 m/s^2

So:

60N = x * 294 N

x = 60 N / 294 N = 0,2

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Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equ

sdas [7]

Answer:

$x_{3}=2.35$

Explanation:

Given $x^2-2x-1=0,x_1=2$

From Newton's method

$x_{n+1}=x_n-\dfrac{f(x_n)}{f'(x_n)}$

$f(x)=x^2-2x-1$

$f'(x)=2x-2$

Now

$x_{2}=x_1-\dfrac{f(x_1)}{f'(x_1)}$

$f(x)=x^2-2x-1$

$f(2)=2^2-2\times 2-1$

f(x)=-1

$f'(2)=2x-2$

$f'(1)=2\times 2-2$

f'(1)=2

$x_{2}=2+\dfrac{1}{2}$

$x_{2}=2.5$

$x_{3}=x_2-\dfrac{f(x_2)}{f'(x_2)}$

$f(2.5)=2.5^2-2\times 2.5-1$

f(2.5)=0.45

$f'(2.5)=2\times 2.5-2$

$f'(2.5)=3$

$x_{3}=2.5-\dfrac{0.45}{3}$

So

$x_{3}=2.35$

8 0

3 years ago

Suppose the block is released from rest with the spring compressed 5.00 cm. The mass of the block is 1.70 kg and the force const

IRISSAK [1]

First, let's calculate the total mechanical energy when the block is at rest and the spring is compressed 5 cm:

$\begin{gathered} ME=PE+KE\\ \\ ME=\frac{kx^2}{2}+\frac{mv^2}{2}\\ \\ ME=\frac{955\cdot0.05^2}{2}+0\\ \\ ME=1.194\text{ J} \end{gathered}$

Now, let's use this total energy to calculate the velocity when the spring is compressed by 2.5 cm:

$\begin{gathered} ME=PE+KE\\ \\ 1.194=\frac{kx^2}{2}+\frac{mv^2}{2}\\ \\ 2.388=955\cdot0.025^2+1.7v^2\\ \\ 1.7v^2=2.388-0.597\\ \\ 1.7v^2=1.791\\ \\ v^2=\frac{1.791}{1.7}\\ \\ v^2=1.0535\\ \\ v=1.026\text{ m/s} \end{gathered}$

Therefore the speed is 1.026 m/s.

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1 year ago

When learning a new exercise what is the first thing you should focus on?

Brums [2.3K]

Answer:

If your form is correct (b)

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2 years ago

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What type of motion occurs when an object spends around and axis without altering its linear position?

ch4aika [34]

I believe it is called centripetal force <span />

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3 years ago

5. A sled with no initial velocity accelerates at a rate of 5.0 m/s2 down a hill. How

ad-work [718]

Answer:

60 m/s

Explanation:

$a = \frac{vf - vi}{t}$

$5.0 = \frac{vf - 0}{12}$

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3 years ago