The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.
<h3>How to solve for the time interval</h3>
We have y = 0.175
y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175
sin (1.25x + 99.6t) = 0.175
sin (1.25x + 99.6t) = 0.5
99.62 = pi/6
t1 = 5.257 x 10⁻³
99.6t = pi/6 + 2pi
= 0.0683
The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.
b. we have k = 1.25, w = 99.6t
v = w/k
99.6/1.25 = 79.68
s = vt
= 79.68 * 0.0683
= 5.02
Read more on waves here
brainly.com/question/25699025
#SPJ4
complete question
A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?
solid
Explanation:
because it has a definite shape and volume
Answer:
the final velocity of the wagon is 6 m/s.
Explanation:
Given;
initial velocity of the wagon, u = 4 m/s
mass of the wagon, m = 35 kg
energy applied to the wagon, E = 350 J
The final velocity of the wagon is calculated as;
E = ¹/₂m(v² - u²)
Therefore, the final velocity of the wagon is 6 m/s.
The component that’s dissolved is called the solvent
Answer:
The speed of the raindrop and the mosquito is 8.02 m/s.
Explanation:
mass of mosquito = m
mass of drop = 45 m
initial velocity of mosquito, u = 0 m/s
initial velocity of drop, u' = 8.2 m/s
During the inelastic collision, the momentum of the system is conserved.
Let the speed of rain drop and the mosquito is v.
Use the conservation of momentum
m x u + 45 m x u' = (m + 45 m) v
m x 0 + 45 m x 8.2 = 46 m x v
v = 8.02 m/s
