20. A 0.450-kg baseball comes off a bat and goes straight up. At a height of 10.0 m, the

Compute the velocity of an electron that has been accelerated through a difference of potential of 100 volts. express your answe

Elodia [21]

The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * $10^{6}$ m/s

Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.

By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.

given

charge of electron = 1.6 × $10^{-19}$ C

mass of electron = 9.1 × $10^{-31}$ kg

Force in an electric field = q*E

potential energy is stored in the form of work done

potential energy = work done = Force * displacement

= q * (E * d)

= q * (V) = 1.6 × $10^{-19}$ * 100

stored potential energy = kinetic energy in electric field

kinetic energy = 1/2 * m * $v^{2}$

= 1/2 * 9.1 × $10^{-31}$ * $v^{2}$

equation both the equations

1/2 * 9.1 × $10^{-31}$ * $v^{2}$ = 1.6 × $10^{-17}$

$v^{2}$ = 0.352 * $10^{14}$ m/s

$v^{2}$ = 35.2 * $10^{12}$

= 5.93 * $10^{6}$ m/s

To learn more about kinetic energy in electric field here

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3 0

1 year ago

Imagine that you are working as a roller coaster designer. You want to build a record breaking coaster that goes 70.0 m/s at the

Rzqust [24]

Wow ! This is not simple. At first, it looks like there's not enough information, because we don't know the mass of the cars. But I"m pretty sure it turns out that we don't need to know it.

At the top of the first hill, the car's potential energy is

PE = (mass) x (gravity) x (height) .

At the bottom, the car's kinetic energy is

   KE = (1/2) (mass) (speed²) .

You said that the car's speed is 70 m/s at the bottom of the hill,
and you also said that 10% of the energy will be lost on the way
down. So now, here comes the big jump. Put a comment under
my answer if you don't see where I got this equation:

   KE = 0.9 PE

(1/2) (mass) (70 m/s)² = (0.9) (mass) (gravity) (height)

Divide each side by (mass):

   (0.5) (4900 m²/s²) = (0.9) (9.8 m/s²) (height)

(There goes the mass. As long as the whole thing is 90% efficient,
the solution will be the same for any number of cars, loaded with
any number of passengers.)

Divide each side by (0.9):

   (0.5/0.9) (4900 m²/s²) = (9.8 m/s²) (height)

Divide each side by (9.8 m/s²):

   Height = (5/9)(4900 m²/s²) / (9.8 m/s²)

      = (5 x 4900 m²/s²) / (9 x 9.8 m/s²)

      = (24,500 / 88.2) (m²/s²) / (m/s²)

      = 277-7/9 meters
      (about 911 feet)

3 0

2 years ago

In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t

galina1969 [7]

Answer:

$W_x = 0.9156\ c$