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Maru [420]
3 years ago
14

In an experiment, scientists test a hypothesis by changing and observing variables

Chemistry
1 answer:
belka [17]3 years ago
6 0
True is the correct answer
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German scientist alfred wiener is best known for what hypothesis?
Leona [35]
He was best known for the Continental Drift 
3 0
3 years ago
What mass of Al(OH)3 is needed to completely react with 17.9g of HCl?
musickatia [10]

Answer:

12.8 g

Explanation:

Step 1: Write the balanced neutralization reaction

Al(OH)₃ + 3 HCl ⇒ AlCl₃ + 3 H₂O

Step 2: Calculate the moles corresponding to 17.9 g of HCl

The molar mass of HCl is 36.46 g/mol.

17.9 g × 1 mol/36.46 g = 0.491 mol

Step 3: Calculate the moles of Al(OH)₃ that completely react with 0.491 moles of HCl

The molar ratio of Al(OH)₃ to HCl is 1:3. The reacting moles of Al(OH)₃ are 1/3 × 0.491 mol = 0.164 mol

Step 4: Calculate the mass corresponding to 0.164 moles of Al(OH)₃

The molar mass of Al(OH)₃ is 78.00 g/mol.

0.164 mol × 78.00 g/mol = 12.8 g

3 0
3 years ago
If you could answer these 2 questions I will give brainliest if you get it right please and thank you!!!
EleoNora [17]

Answer:

1. D.) Structural Data

2. C.) Overproduction

Explanation:

1. Structural Data was used to determine the similarities between the two species.

2. In biological terms, overproduction means that a generation had more offspring than can be supported by the environment. In this case, its a stronger hatchling beating out the waker hatchlings.

8 0
4 years ago
What is the change in the freezing point of water when 68.5 g of sucrose is
mr Goodwill [35]
The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
7 0
4 years ago
Read 2 more answers
A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t
drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t} (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>  

(a) We can calculate the energy (ΔU) using equation (1):

\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J  

(b) The work is related to pressure and volume by:

\Delta W = -p \Delta V

<em>where p: pressure and ΔV: change in volume = V final - V initial      </em>

\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J

(c) By the definition of Energy, we can calculate q:

\Delta U = \Delta W + \Delta q

<em>where Δq: is the heat transfer </em>

\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J    

I hope it helps you!  

6 0
4 years ago
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