What is the change in the freezing point of water when 68.5 g of sucrose is
2 answers:
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Answer:
option D is correct
D. This solution is a good buffer.
Explanation:
TRIS (HOCH)
CNH
if TRIS is react with HCL it will form salt
(HOCH)
CNH
+ HCL ⇆ (HOCH
)
NH
CL
Let the reference volume is 100
Mole of TRIS is = 100 × 0.2 = 20
Mole of HCL is = 100 × 0.1 = 10
In the reaction all of the HCL will Consumed,10 moles of the salt will form
and 10 mole of TRIS will left
hence , Final product will be salt +TRIS(9 base)
H = Pk + log (base/ acid)
8.3 + log(10/10)
8.3
Answer:
3.2L
Explanation:
PV=nRT
since pressure and temperature are held constant we have V=nR
R is a constant also,
Thus;
v1=1.5L , n1=3mol, n2=1.4mol
v2=
v2=3.2L