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elena-14-01-66 [18.8K]

3 years ago

12

An ionic bond involves _____.A. an attraction between ions of opposite chargeB. water avoidanceC. the sharing of a single pair o

f electronsD. no atoms other than sodium and chlorineE. the unequal sharing of an electron pair

1 answer:

allochka39001 [22]3 years ago

8 0

Answer: D i think

Explanation: Im sorry if it is wrong lol!! I pretty sure thats the answer...

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Who were good friends in one day a stranger came<br><br>

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Answer:

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Explanation:

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Polymerization is the process of linking smaller molecules to form long chains of higher molecular weight. True or False

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True is correct answer.

Polymerization is the process of linking it has a smaller molecules to form has a long chains of higher molecular weight.

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Read 2 more answers

One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867

Thepotemich [5.8K]

<u>Answer:</u>

(A)

Density = Mass / Volume

So

Mass = Density × Volume

$= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene$

$1C_6 H_5 CH_3 + 9 O_2 > 7 CO_2 + 4 H_2 O$

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of $CO_2$ gas and 4 moles of $H_2 O$ Vapour

So the mole ratio is 1 : 11

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $$

(C)

1mole contains $6.022\times10^{23}$ molecules

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $$

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Two atoms of calcium and one molecule of oxygen gas react and yield two molecules of calcium oxide.

Vitek1552 [10]

2Ca + O2 ——————-> 2CaO2

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But in your own words

8_murik_8 [283]

Answer:

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