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elena-14-01-66 [18.8K]
3 years ago
12

An ionic bond involves _____.A. an attraction between ions of opposite chargeB. water avoidanceC. the sharing of a single pair o

f electronsD. no atoms other than sodium and chlorineE. the unequal sharing of an electron pair
Chemistry
1 answer:
allochka39001 [22]3 years ago
8 0

Answer: D i think

Explanation: Im sorry if it is wrong lol!! I pretty sure thats the answer...

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A 10.00 g sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 g BaSO4 (M- 233.4). W
aliina [53]

Answer:

The salt is barium chloride.

Explanation:

BaX_2++Na_2SO_4\rightarrow BaSO_4+2NaX

Moles of barium sulfate =\frac{11.21 g}{233.38 g/mol}=0.0480 mol

According to reaction, 1 mol of barium sulfate is produced from 1 mol of BaX_2.

Then 0.0480 moles will be produced from:

\frac{1}{1}\times 0.0480 mol=0.0480 mol of BaX_2.

Mass of BaX_2 used = 10.00 g

Moles of BaX_2 =\frac{10.00 g}{\text{Molar mass}}[/tex]

0.0480 mol=\frac{10.00}{\text{Molar mass}}

Molar mass of BaX_2 = 208.33 g/mol

The nearest answer to our answer is BaCl_2=208.2 g/mol.

The correct answer barium chloride with molar mass of 208.2 g/mol.

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3 years ago
Each of the diagrams below shows an electrically neutral atom. fill in the missing number of protons (n) neutrons (and), electro
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What is the diagram?
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Which property of a body cannot be changed if a force is applied to it?
prohojiy [21]
The answer is it’s mass
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2 years ago
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Wastewater discharged into a stream by a sugar refinery contains 3.40 g of sucrose (C12H22O11) per liter. A government-industry
Ipatiy [6.2K]

<u>Answer:</u> The pressure that must be applied to the apparatus is 0.239 atm

<u>Explanation:</u>

To calculate the osmotic pressure, we use the equation for osmotic pressure, which is:

\pi=iMRT

or,

\pi=i\times \frac{m_{solute}}{M_{solute}\times V_{solution}\text{ (in L)}}}\times RT

where,

\pi = osmotic pressure of the solution

i = Van't hoff factor = 1 (for non-electrolytes)

m_{solute} = mass of sucrose = 3.40 g

M_{solute} = molar mass of sucrose = 342.3 g/mol

V_{solution} = Volume of solution = 1 L

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 20^oC=[20+273]K=293K

Putting values in above equation, we get:

\pi =1\times \frac{3.40g}{342.3g/mol\times 1}\times 0.0821\text{ L. atm }mol^{-1}K^{-1}\times 293K\\\\\pi =0.239atm

Hence, the pressure that must be applied to the apparatus is 0.239 atm

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3 years ago
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