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Masja [62]
3 years ago
7

PLEASE HELP ASAP 98 POINTS!!!!!!! ALL I NEED YOU GUYS TO DO IS WRITE A ONE PARAGRAPH REFLECTION ON ECLIPSES AND WRITE IT AS IF Y

OU WHERE EXPLAINING IT TO A FRIEND
HERE IS A BETTER WAY TO EXPLAIN IT
Provide a description of how you made your model and how it demonstrates eclipses or lunar phases.
Include a one-paragraph reflection on the success of your model in explaining your event.

DON'T WORRY ABOUT THE MODEL I HAVE IT COVERED.
Physics
2 answers:
makvit [3.9K]3 years ago
6 0

A eclipse starts when one object in space is blocking an observer. Most commonly known as the moon blocking the sun. For us having a visual on eclipses we normally have two eclipses. We have the solar eclipse and the lunar eclipse. These are both very important on the timing and the cycles of the moon. A solar eclipse happens when the moon moves in front of the sun. This will cause a shadow to fall on only a few certain places on earth. Then a lunar eclipse is when the Sun, moon, and earth are perfectly aligned. With the earth being the middle the Sun casts its rays and causes a huge shadow on the moon.

Hope this helped!

Ket [755]3 years ago
6 0

check out my model showing the sun, earth n moon. u can see as the moon moves around the earth, its path is at a angle w earth's path around the sun. so moon's reflection of sunlight as seen from earth changes every night. it is called lunar phases: going crescent moon to full moon n back. eclipse happens when earth is between sun and moon and blocks part of the sun light. earth's shadow covers part or all of the moon. it is called lunar eclipse.


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Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass i
Fed [463]

Answer:25 N

Explanation:

Given

mass of 5 , 3 & 2 kg blocks lie on floor

Force on 50 N pushes the 5 kg box

Let N_1 be the reaction on 2 kg box therefore

N_1=2\times a

where a is the acceleration of the system

N_2=reaction on 3 kg block by 5 kg block

N_2-N_1=3a

N_2=5a

Now for 5 kg block

F-N_2=5a

F=10a

a=\frac{F}{10}=5 m/s^2

Force exerted by 5 kg block on 3 kg block is

N_2=5\times 5=25 N

6 0
3 years ago
How do rechargeable batteries work? When a rechargeable battery is connected to electricity it changes the pressure inside and a
aalyn [17]

Question:

How do rechargeable batteries work?

Answer:

When a rechargeable battery is connected to electricity it changes the pressure inside and allows the rubber membrane to expand, thus releasing more energy next time its used. When plugged into the wall the electrons are sent back to rebuild the original dry cell (or metal). Rechargeable batteries are made exclusively of nitrogen which when exposed to electricity from and outlet can store a charge. When a battery is zapped by the electricity from the outlet it resets the system.

7 0
2 years ago
How fast must a 1000 kg car be moving to have a kinetic energy of:
VMariaS [17]

Answer:

\mathrm{(a)}\: 2\: \mathrm{m/s}\\\mathrm{(b)}\: 20\: \mathrm{m/s}\\

Explanation:

The kinetic energy of an object is given by KE=\frac{1}{2}mv^2 where m is the mass of the object and v is the velocity of the object.

We can set up the following equations with the information given:

\mathrm{(a)}\: 2.0\cdot 10^3=\frac{1}{2}\cdot 1000\cdot v^2, \\v=\fbox{$2\: \mathrm{m/s}$}

For part B, we have the same equation, but kinetic energy is now 2.0\cdot 10^5.

Therefore:

\mathrm{(b)}\: 2.0\cdot 10^5=\frac{1}{2}\cdot 1000\cdot v^2, \\v=\fbox{$20\: \mathrm{m/s}$}.

6 0
3 years ago
Help with science for A P E X
eimsori [14]

Answer:

inertia

Explanation:

7 0
4 years ago
42,43 and 44 please
Mariana [72]
42) The sailboat travels east with velocity v_e=30 mph, while the current moves south with speed v_s=30 mph. Since the two velocities are perpendicular to each other, he resultant velocity will be given by the Pytagorean theorem:
v= \sqrt{v_e^2+v_s^2}= \sqrt{(30)^2+(30)^2}=42 mph
and the direction is in between the two original directions, therefore south-east. So, the correct answer is
D) 42 mph southeast

43) Since the light moves by uniform motion, we can calculate the distance corresponding to one light year by using the basic relationship between velocity, space and time. In fact, we know the velocity:
v=300,000,000 m/s=3 \cdot 10^8 m/s
and the time is one year, corresponding to:
t=32,000,000 s=3.2 \cdot 10^7 s
therefore, the distance corresponding to one light year is:
S=vt=(3\cdot 10^8 m/s)(3.2 \cdot 10^7 s)=9.6 \cdot 10^{15}m
Therefore, the correct answer is D.

44) For the purpose of the problem, we can assume that the light travels instantaneously from the flash to us (because the distances involved are very small), so the time between the flash and the thunder corresponds to the time it took for the sound to travel to us.
The speed of sound is
v=1100 ft/s=750 mph=335 m/s
And since the time between the flash and the thunder is t=3 s, the distance is
S=vt=(335 m/s)(3 s)=1005 m=0.62 miles
Therefore, the correct answer is A) 3/5 mile.
6 0
3 years ago
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