Answer: 6
Step-by-step explanation:
2 free books7 purchased books=? free books21 purchased booksCompare the denominators.2 free books7purchased books=? free books21purchased booksTo get from 7 to 21, multiply by 3. Multiply the numerator and denominator by 3 to find the number of free books Larry got.2 free books37 purchased books3=6free books21 purchased booksLarry got 6 free books
Answer:
39 X 10=75
Step-by-step explanation:
♀️
pH = f(x) = -log₁₀x
1. Graphs
I used Excel to calculate the pH values and draw the graphs (see the Figure).
f(x) and f(x) +1 are plotted against the left-hand axis, while f(x+ 1) is plotted against the expanded right-hand axis.
The points at which pH = 0 and pH = 1 are indicated by the large red dots.
2. x = 0.5
When x = 0.5, pH ≈0.30. The point is indicated by the red diamond.
3. Transformations
(a) ƒ(x) = -log(x) + 1
This function has no y-intercept, because log(0) is undefined.
(b) ƒ(x +1) = -log(x + 1)
f(0) = -log(0 + 1) = -log(1) = 0
This function has a y-intercept at (0,0).
hope this helps please mark me brainliest!
Answer:
<em> Linear model
</em>
The function f(x) which represents the total amount in the savings account in x months is given by: f(x)=25x+2000
Step-by-step explanation:
Given:
Enrico deposited $2000 in a savings account.
Each month he will deposit additional $25.
This shows that the rate at which the amount is increasing each month is constant.
Therefore, the model will be linear with a slope 25.
So , if x represents the number of months.
and f(x) represents the corresponding amount in the account.
Then the function f(x) is given by: f(x)=25x+2000
Answer:
third option
Step-by-step explanation:
Given
3 ![\left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%265%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiply each element in the matrix by 3
= ![\left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%285%29%5C%5C3%281%29%263%280%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}-6&15\\3&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-6%2615%5C%5C3%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
