The base fare per ride on the MTA bus or subway is $2.75, but you get a 5% discount with a purchase. A weekly unlimited MetroCar
1 answer:
"13" or "more than 13" rides will make the weekly unlimited pass more cost effective. A further solution is provided below.
The given values are:
- Base fare per ride = $2.75
- Discount = 5%
- Weekly unlimited Metro Card costs = $32
The Fare after discount will be:
=
=
=
= ($)
hence,
In $32, the minimum number of rides will be:
=
=
or,
= 13
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Answer:
a) = 0.588
b) 23
c) 47
Step-by-step explanation:
To find a solution for this question we must consider the following:
If we’d like to know the probability of two or more people having the same birthday we can start by analyzing the cases with 1, 2 and 3 people
For n=1 we only have 1 person, so the probability of sharing a birthday is 0 (
=0)
For n=2 the probability can be calculated according to Laplace’s rule. That is, 365 different ways that a person’s birthday coincides, one for every day of the year (favorable result) and 365*365 different ways for the result to happen (possible results), therefore,
For n=3 we may calculate the probability that at least two of them share their birthday by using the opposite probability P(A)=1-P(B). That means calculating the probability that all three were born on different days using the probability of the intersection of two events, we have:
So, the second person’s birthday might be on any of the 365 days of the year, but it won’t coincide with the first person on 364 days, same for the third person compared with the first and second person (363).
Let’s make it general for every n:
Now, let’s answer the questions!
a) Remember we just calculated the probability for n people having the same birthday by calculating 1 <em>minus the opposite</em>, hence <em>we just need the second part of the first calculation for</em> , that is:
We replace n=20 and we obtain (you’ll need some excel here, try calculating first the quotients then the products):
= 0.588
So, we have a 58% probability that 20 people chosen randomly have different birthdays.
b) and c) Again, remember all the reasoning above, we actually have the answer in the last calculation for pn:
But here we have to apply some trial and error for 0.50 and 0.95, therefore, use a calculator or Excel to make the calculations replacing n until you find the right n for =0.50 and
=0.95
b) 0.50 = 365!/(365^n)*(365-n)!
n
1 0
2 0,003
3 0,008
…. …
20 0,411
21 0,444
22 0,476
23 0,507
The minimum number of people such that the probability of two or more of them have the same birthday is at least 50% is 23.
c) 0.95 = 365!/(365^n)*(365-n)!
We keep on going with the calculations made for a)
n
… …
43 0,924
44 0,933
45 0,941
46 0,948
47 0,955
The minimum number of people such that the probability of two or more of them have the same birthday is at least 95% is 47.
And we’re done :)