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Artemon [7]
3 years ago
15

Simplify . 7(8-1)+(-1) ^)2/1+2^2

Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

\frac{50}{5}  = 10

Step-by-step explanation:

\frac{7(8 - 1) + ( - 1 {)}^{2} }{1 +  {2}^{2} }

\frac{7 \times 7 + ( - 1 {)}^{2} }{1 +  {2}^{2} }  =  \frac{7 \times 7 + 1}{1 +  {2}^{2} }

\frac{7 \times 7 + 1}{1 + 4}  =  \frac{49 + 1}{1 + 4}  =  \frac{49 + 1}{5}

=  \frac{50}{5}  = 10

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A length of ribbon measures 3 yd 1 ft 10 in.
Elza [17]

Answer :   11  3/5 inches each or 11.6 inches each

Step-by-step explanation:

There are 3+1 foot=4ft  each foot is 12 inches4x12=48+10=58

So you have 58 inches of ribbon.   58/5 =11  3/5 inches each or 11.6 inches each

6 0
3 years ago
There are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
bearhunter [10]

Answer:

<h3>The ratio of technicians to all helpers  is 11 : 7, or \frac{11}{7} or 11 to 7.</h3>

Step-by-step explanation:

  • Given that there are 7 ushers and 11 technicians helping at the Harper Middle School fall play.
  • Let x be the number of ushers ( or helpers ).
  • Therefore x=7 helpers.
  • Let y be the number of technicians.
  • Therefore y=11 technicians.
<h3>To find the ratio of technicians to all helpers :</h3>

That is to find the ratio of y to x.

We can write the ratio of technicians to all ushers(helpers) as y : x

Which implies that 11 : 7,  (since y=11 and x=7)

Or \frac{11}{7} or 11 to 7

<h3>The ratio of technicians to all helpers  is 11 : 7, or \frac{11}{7} or 11 to 7</h3>
4 0
3 years ago
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d1i1m1o1n [39]
Is 20 and answer because I did this on a calculator and this is the only one to me that would make since
6 0
2 years ago
A number between 1 and 3 is chosen 30 times. Results are shown in the table below. What is the experimental probability of picki
GuDViN [60]
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8 0
3 years ago
-3x + 3y =3<br> -5x + y =13 Solve as a whole number
anzhelika [568]

Answer:

X = 3 x − 14

y = − x + 5

Step-by-step explanation:

Solve for the first variable, then substitute the result into the other equation.

4 0
2 years ago
Read 2 more answers
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