1.785714285714286 should be your answer
Answer:
Step-by-step explanation:
a. The vertex is (1, -9). False. The vertex is (-1, -9).
b. The graph opens upward. True. That coefficient '6' is positive.
c. The graph is obtained by shifting the graph of f(x) = 6(x + 1)2 up 9 units. False. It's DOWN 9 units.
d. The graph is steeper than the graph of f(x) = x^2. True. The given function increases 6 times faster than does x^2.
e. The graph is the same as the graph of f(x) = 6x2 + 12x - 3.
Let's put f(x) = 6(x + 1)^2 -9 into standard form. Expanding the first term, we get f(x) = 6(x^2 + 2x + 1) - 9, or f(x) = 6x^2 + 12x + 6 - 9. YES, TRUE
Answer:
Interval for the function has local minimum of 0 is [2,4].
Step-by-step explanation:
You need to find the local minimum of 0 in the given function's graph.
In mathematics, local minimum is a point on a graph whose value is less than all other points near it.
See that, graph value 0 is lie on the x = 3 and in interval x = 2 to x = 4
So, final answer is :
Interval for the function has local minimum of 0 is [2,4].That's the final answer.
hope it helps
Use the compound interest formula.
A = P*(1 +r/n)^(n*t)
where P is the principal, r is the annual rate, n is the number of compoundings per year, and t is the number of years.
For the first investment, ...
A = 208,000*(1 +.08/4)^(4*5) = 309,077.06
For the second investment, ...
A = 218,000*(1 +.07/2)^(2*4) = 287,064.37
Totaling both investments at maturity, Megan has $596,141.43.
15,000 --> fifteen thousand
400 --> four hundred
00 --> zero
9 --> nine
If you put this all together it gives you fifteen thousand four hundred and nine.