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luda_lava [24]
2 years ago
8

Is the equation y=9x linear

Mathematics
2 answers:
GREYUIT [131]2 years ago
7 0
It is linear because it’s a straight line

ludmilkaskok [199]2 years ago
4 0

Answer:

Linear

Step-by-step explanation:

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be  0  or  1  for each of its variables. In this case, the degree of variable  y  is  1  and the degree of variable  x  is  1 .

Linear

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What is the area of this figure?
coldgirl [10]
Answer: 102

-----------------------------------------------

We'll use the formula 
A = h*(b1+b2)/2
where
A = area of trapezoid
h = height
b1 & b2 are the parallel bases

In this case,
b1 = 6+7 = 13
b2 = 21
h = 6

Making the area to be
A = h*(b1+b2)/2
A = 6*(13+21)/2
A = 6*(34)/2
A = 204/2
A = 102

Side Note: We don't use the slanted side of 10 cm at all

3 0
3 years ago
If f(x)=x+4 and g(x)=x^3 what is (g*f)(-3)
Molodets [167]

Step-by-step explanation:

g*f(x)=g(x+4)=(x+4)³

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= 1³=1

4 0
3 years ago
All geometric figures,shapes,and solids can be named using sets of
Naddika [18.5K]

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All geometric figures, shapes and solids can be named as a sets of surface regions and plane regions and they all lie in three dimensional spaces.

Step-by-step explanation:


7 0
3 years ago
The owner of a small store buys coats for 55.00 each <br><br> He sells the coats for 66.00 each
liubo4ka [24]

he must buy 24 jackets to get atheist 260 dollars

7 0
2 years ago
Find all degree solutions in the interval 0° ≤ θ &lt; 360°. If rounding is necessary, round to the nearest tenth of a degree. Us
xenn [34]

Answer:

\theta_{1} \approx 30.473^{\textdegree}

\theta_{2} \approx 120.473^{\textdegree}

\theta_{3} \approx 210.473^{\textdegree}

\theta_{4}\approx 300.473^{\textdegree}

Step-by-step explanation:

The equation needs to be rearranged in terms of one trigonometric function:

5\cdot \sin 2\theta - 9\cdot \cos 2\theta = 0

5\cdot \tan 2\theta - 9 = 0

5\cdot \tan 2\theta = 9

\tan 2\theta = \frac{9}{5}

\theta = \frac{1}{2}\cdot \tan^{-1} \left(\frac{9}{5} \right)

The tangent function has positive values in the 1st and 3rd Quadrants. Then, the solutions are:

\theta_{1} \approx 30.473^{\textdegree}

\theta_{2} \approx 120.473^{\textdegree}

\theta_{3} \approx 210.473^{\textdegree}

\theta_{4}\approx 300.473^{\textdegree}

3 0
2 years ago
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