(m^(6)n^(3))/(m^(2)n^(6))

Michael puts 3 beads next to each other on a pice of string to make a bracelet. Each bead has a width of 5/6 inch. Which express

pentagon [3]

Answer:

3 (5/6)

5/2

Step-by-step explanation:

Hi, to answer this question we have to write an expression with the information given.

The total width of the three beads must be equal to the number of beads (3) multiplied by the length of each bead (5/6)

Mathematically speaking:

3 (5/6)

Solving:

5/2

Feel free to ask for more if needed or if you did not understand something.

8 0

3 years ago

If you subtracted 3 from the exponent in an exponential function, what would happen to the graph? A) It would move up 3 B) It wo

kolezko [41]

Answer: The correct answer is D!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s

Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question, we have that:

$\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2$

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when $X = 260$ . So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{260 - 270}{21.2}$

$Z = -0.47$

$Z = -0.47$ has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0

3 years ago

A jacket that originally sold for $60.00 was on sale for 10% off. When it didn't sell after several weeks, the sale price was di

sammy [17]

The final price of the jacket was $32.40 after both the 10% and 40% discount. The total discount is NOT equal to a 50% discount. When 10% off, the price was $54, bringing the next 40% off to a whole different number, not necessarily off the original price.

I don't know if that makes sense to you, sorry xD

7 0

3 years ago

I need help ASAP please

Ganezh [65]

Answer:

hi

Step-by-step explanation:

6 0

3 years ago