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melamori03 [73]
3 years ago
5

1 question I still have about Baroque music​

Physics
2 answers:
Vika [28.1K]3 years ago
8 0

Answer:

yes

Explanation:

yesim guessing that yes u still have

LenaWriter [7]3 years ago
3 0

Answer:

Baroque Music:

Baroque music is another way to refer to Western classical music composed between approximately 1600 and 1750. Some of the most famous Baroque music composers included Bach, Handel, and Vivaldi.

pa follow at pa brainlest answer na den

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The average kinetic energy of uf6(g) is 4.98 kj/mol at some temperature. what is the average kinetic energy of sf6(g) at that sa
Darya [45]
4.98 kJ/mol would be the answer I believe :) hope this helped
5 0
3 years ago
Read 2 more answers
In order to move a bag of dog food across a 10 meter room, you apply 20 newtons of force. How much work was done?
9966 [12]
The work done is calculated by multiplying the Force by the distance. So, 10x20 = 200 joules.
5 0
3 years ago
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A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 71.0 N is required to set the block in motio
Julli [10]

Answer:

(a) \mu_s=0.25

(b) \mu_k=0.20

Explanation:

According to Newton's second law:

\sum F_y:N=mg\\\sum F_x:F_a=F_f

Recall that the frictional force is related jointly with the coefficient of friction and normal force F_f=\mu N. Replacing in the above equation, we get the coefficient of friction:

F_a=\mu N=\mu mg\\\mu=\frac{F_a}{mg}

(a) The  coefficient of static friction is related with the force required to set the block in motion:

\mu_s=\frac{71N}{29kg*9.8\frac{m}{s^2}}\\\mu_s=0.25

(b) The  coefficient of kinetic friction is related with the force required to keep the block moving with constant speed:

\mu_k=\frac{56N}{29kg*9.8\frac{m}{s^2}}\\\mu_k=0.20

3 0
3 years ago
A block of mass 4 kilograms is initially moving at 5m/s on a horizontal surface. There is friction between the block and the sur
emmasim [6.3K]

• Net vertical force on the block:

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

(<em>n</em> = magnitude of normal force, <em>w</em> = weight)

<em>n</em> = <em>w</em> = <em>m g</em>

(<em>m</em> = mass, <em>g</em> = 9.8 m/s²)

<em>n</em> = (4 kg) (9.8 m/s²) = 39.2 N

• Net horizontal force:

∑ <em>F</em> = -<em>f</em> = <em>m a</em>

(<em>f</em> = mag. of friction, <em>a</em> = acceleration)

We have <em>f</em> = <em>µ</em> <em>n</em> = 0.5 (39.2 N) = 19.6 N, so

-19.6 N = (4 kg) <em>a</em>

<em>a</em> = -4.9 m/s²

With this acceleration, the block comes to a rest from an initial speed of 5 m/s, so that it travels a distance ∆<em>x</em> in this time such that

0² - (5 m/s)² = 2 (-4.9 m/s²) ∆<em>x</em>

∆<em>x</em> = (25 m²/s²) / (9.8 m/s²) ≈ 2.55 m ≈ 2.6 m

8 0
3 years ago
One way to conserve energy is to replace incandescent light bulbs with compact fluorescent bulbs. The fluorescent bulb typically
NemiM [27]

Answer:

     cos to = $ 24

Explanation:

When replacing the bulb only 25% of the energy is used, therefore

          W = 0.25 100

          W = 25 W

Let's look for the energy in the life of the bulb

          E = 25 10⁻³ 12000

          E = 300 Kwh

now we can calculate the cost using a direct proportion rule.

          Cost = 0.08 300

          cos to = $ 24

4 0
3 years ago
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