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Olegator [25]
3 years ago
15

The average kinetic energy of uf6(g) is 4.98 kj/mol at some temperature. what is the average kinetic energy of sf6(g) at that sa

me temperature?
Physics
2 answers:
pashok25 [27]3 years ago
6 0

Answer:

The average kinetic energy of SF₆(g) is 4.98 kj/mol.

Explanation:

Given that,

Kinetic energy  of UF₆(g)=4.98\ kj/mol

We need to calculate the average kinetic energy of SF₆(g)

Using formula of average kinetic energy

E_{avg}=\dfrac{3}{2}kT

E_{avg}=\dfrac{3}{2}\dfrac{RT}{N_{A}}

Where, k = Boltzmann constant

N_{A} =Avogadro number

R =gas constant

Here, average kinetic energy depends only on temperature not on special molar mass

So, The SF₆(g) average kinetic energy is same as UF₆(g

Hence, The average kinetic energy of SF₆(g) is 4.98 kj/mol.

Darya [45]3 years ago
5 0
4.98 kJ/mol would be the answer I believe :) hope this helped
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According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>



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<h2>T^{2} =\frac{4\pi^{2}}{GM}a^{3}    (1) </h2>

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a=4.22(10^{5})km=4.22(10^{8})m  is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)



If we want to find the period, we have to express equation (1) as written below and substitute all the values:



<h2>T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}    (2) </h2>

T=\sqrt{\frac{4\pi^{2}}{6.674(10^{-11})\frac{m^{3}}{kgs^{2}}1.9(10^{27})kg}(4.22(10^{8})m)^{3}}    



T=\sqrt{\frac{2.966(10^{27})m^{3}}{1.268(10^{17})m^{3}/s^{2}}}    



T=\sqrt{2.339(10^{10})s^{2}}    



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<h2>T=152938.0934s    (3) </h2>

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<h2>T=42.482h     </h2>

Therefore, the answer is:



The orbital period of Io is 42.482 h



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