It maybe they must run the query to display the corresponding results.
Answer:
Option(d) i.e "document camera " is the correct answer for the given question
Explanation:
The document camera is mainly preferable when our aim displays the object into a large audience with the help of document camera Gwen displays her speech into the classroom.
The hard copy is simply placed in the document camera, it takes the hard copy as an image format and gives the live image of the speech with the help of a monitor .
- The main advantage of a document camera is that they provide greater flexibility.
- Traditional whiteboard, overhead projector, flip charts not the best solution for that problem also they do not provide flexibility so they are all incorrect options.
Answer:
No, the receiver cannot be absolutely certain that no bit errors have occurred. This is because of the manner in which the checksum for the packet is calculated. If the corresponding bits (that would be added together) of two 16-bit words in the packet were 0 and 1 then even if these get flipped to 1 and 0 respectively, the sum still remains the same. Hence, the 1s complement the receiver calculates will also be the same. This means the checksum will verify even if there was transmission error
Explanation:
Answer:
One major sign of a computer being hijacked is the use of system resource by unknown programs. For example, full memory, high cpu usage, slow start up, crashes and errors, and low avalible storage space.
Explanation:
Answer:
(A) Always true
<em></em>
Explanation:
Given
Boolean variables x and y
Required
What is (x && y) || !(x && y)
Irrespective of what x or y is, the x && y is always true
Take for instance:
<em>x = true;</em>
<em>y = true;</em>
<em>x&&y will also be true because the values of x and y were not altered</em>
<em />
<em>And this is true for whatever boolean value x or y assume</em>
<em />
Having said that:
x&&y = true
So, the expression is analysed as follows:
(x && y) || !(x && y)
Substitute true for x&&y
(true) || !(true)
<em>!(true) = false</em>
So, the expression becomes:
true || false
|| represents the OR operator; and it returns true if at least one of the conditions is true.
By this:
true || false = true
<em>Option (A) Always true </em><em>answers the question.</em>
