Question

The rhumbas has a perimeter or 16 and height of 3 what is the area ?

Answer 1

I think the answer is 15 cuz if the height is 3; 3 on each side is 6 so 6-16=10 and 10 divided by 2 for the two others sides is 5… and 5x3=15

Answer 2

Answer:

$A=\frac{3\sqrt{55}}{2}$

Step-by-step explanation:

For a height h, a perimeter P, and an area A, use the following formula:

$A=\frac{1}{4}h\sqrt{P^{2}-4h^{2} }$

Next, replace the variables with the given values:

$A=\frac{1}{4}(3)\sqrt{(16)^{2}-4(3)^{2} }$

Solve the inside of the square root:

$A=\frac{1}{4}(3)\sqrt{256-36}\\A=\frac{1}{4}(3)\sqrt{220}$

Multiply outside of the square root:

$A=\frac{3}{4}\sqrt{220}$

Simplify the square root:

$A=(\frac{3}{4})2\sqrt{55}$

Multiply outside of the square root once more:

$A=\frac{3}{2}\sqrt{55}$

Simplify:

$A=\frac{3\sqrt{55}}{2}$, or ≈ 11.12429773