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Dafna11 [192]
4 years ago
6

Take apart the number to make a 10. Then subtract.

Mathematics
1 answer:
Licemer1 [7]4 years ago
4 0

Answer:

This is one of a variety of "subtraction solutions"--basically a different way to subtract by breaking numbers down into 10-digit chunks.  It's not especially helpful for small subtraction problems, but as math gets more complicated, this method will come in handy.

Step-by-step explanation:

Here's an example: Jim had a bag of 15 jelly beans.  He eats 8.  How many jelly beans does he have left?  <u>Take apart the number to make a 10. Then subtract.</u>

Here, you need to "take apart" the 8 to make your 15 jelly beans 10, then you subtract the remainder of 8 to get your solution.  In other words,

 --"take apart" 8 into 5 and 3 (because you're going to need a 5 to make 15 into 10).  15 minus 5 equals 10.  HOORAY!  You have your 10.  Now, subtract the remaining 3.  10 minus 3 equals 7.  Huzzah--your final answer!

On paper, the problem looks like this:

<u>15 - 8 (</u><u>5, 3</u><u>) = ?</u>

15 - 5 = 10

10 - 3 = 7

So...15 - 8 = 7

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
F(x)=9x+5, find f^-1(x).
lidiya [134]

Answer:

interchange the role of x and y

x=9y+5

x-5=9y

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9

so,f^-1(x)= <u>x-5</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>9

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4 0
3 years ago
Four times a divided by two equals 5.2
Anna71 [15]

Initial equation:

4a / 2 = 5.2

Multiply both sides by 2:

4a = 10.4

Divide both sides by 4:

a = 2.6

Hope this helps!! :)

4 0
4 years ago
Read 2 more answers
V(t), left parenthesis, t, right parenthesis models the number of visitors in a park as a function of the outside temperature t
Kruka [31]

Answer:

The number of visitors increases at the same rate over both intervals

Step-by-step explanation:

The unit rate at which the number of visitors in the park increases over a given temperature interval is called the average rate of change, or ARCARCA, R, C.

To find the average rate of change of a function over an interval, we need to take the total change in the function value over the interval and divide it by the length of the interval.

Hint #22 / 3

We are asked to compare the rates at which the number of visitors increases over the interval between an outside temperature of 181818 degrees Celsius and 202020 degrees Celsius, and over the interval between an outside temperature of 202020 degrees Celsius and 272727 degrees Celsius. These correspond to the domain intervals [18,20][18,20]open bracket, 18, comma, 20, close bracket and [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Let's calculate the average rate of change of VVV over those intervals:

ARC_{[18,20]}ARC

[18,20]

​

A, R, C, start subscript, open bracket, 18, comma, 20, close bracket, end subscript ARC_{[20,27]}ARC

[20,27]

​

A, R, C, start subscript, open bracket, 20, comma, 27, close bracket, end subscript

\begin{aligned} \dfrac{V(20)-V(18)}{20-18}&=\dfrac{18-10}{2}\\\\&=\dfrac{8}{2}\\\\&=4\end{aligned}\quad

20−18

V(20)−V(18)

​

​

 

=

2

18−10

​

=

2

8

​

=4

​

 \begin{aligned} \dfrac{V(27)-V(20)}{27-20}&=\dfrac{46-18}{7}\\\\&=\dfrac{28}{7}\\\\&=4\end{aligned}

27−20

V(27)−V(20)

​

​

 

=

7

46−18

​

=

7

28

​

=4

​

Hint #33 / 3

The average rate of change over the interval [18,20][18,20]open bracket, 18, comma, 20, close bracket is the same as the average rate of change over the interval [20,27][20,27]open bracket, 20, comma, 27, close bracket.

Therefore, the number of visitors increases at the same rate over both intervals.

7 0
3 years ago
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