The answers to the question are are the equations
y = 0.08x²-1.6x+13
y = 0.08(x-10)²+5
<h3>How to solve for the system of equations</h3>
David starts at (20, 13) and skates along a path that can be modeled by a quadratic function with a vertex at (10, 5).
Vertex form of quadratic function is
y = 
13 = a(x-10)²+5
let x = 20
a(20-10)²+5
13 = 100a + 5
take like terms
13 - 5 = 100a
8 = 100a
divide through by 100
a = 0.08
hence the equation would be
y = 0.08(x-10)²+5
Read more on equations here:
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Answer:
I think the answer is b
Step-by-step explanation:
3cos(x)+3
Answer:
7y^2 - y^2z - 10yz-5
C. 7 y squared minus y squared z minus 10 y z minus 5
Step-by-step explanation:
A. y squared minus y squared z minus 10 y z minus 5
B. y squared minus y squared z minus 5 y z minus 5
C. 7 y squared minus y squared z minus 10 y z minus 5
D. 7 y squared minus y squared z minus 2 y z minus 5
Given:
3y^2 - 6yz - 7 + 4y^2 - 4yz + 2 - y^2z
Collect like terms in the expression
3y^2 + 4y^2 - 6yz - 4yz - y^2z - 7 + 2
Simplify
7y^2 - 10yz - y^2z - 5
Rewritten as
7y^2 - y^2z - 10yz-5
Option C. 7 y squared minus y squared z minus 10 y z minus 5
Is the answer
Answer: y=3x+12
explanation: just add the 3x to the 12
3x + 4y = 18......(2,3)
3(2) + 4(3) = 18
6 + 12 = 18
18 = 18...correct
2x - 2y = 2....(2,3)
2(2) - 2(3) = 2
4 - 6 = 2
-2 = 2...incorrect
when (2,3) is subbed into equation 1, it is true
when (2,3) is subbed into the second equation, it is false
the ordered pair (2,3) is not a solution to the system of linear equations
