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3 years ago

One - step equation -104 = 8x please help I don't know and I have tried for an hour now.

Mathematics

2 answers:

dmitriy555 [2]3 years ago

4 0

Answer:

$\boxed {\boxed {\sf x= -13}}$

Step-by-step explanation:

We are asked to solve the following one-step equation.

$-104 = 8x$

We solve the equation by solving for x. We must isolate the variable by performing the inverse operation.

x is being multiplied by 8 (8x = 8*x). The inverse operation of multiplication is division. Divide both sides of the equation by 8. This eliminates the 8 on the right side of the equation so only x remains.

$\frac {-104}{8}= \frac{8x}{8}$

$\frac {-104}{8}= x$

$-13=x$

We can check our answer by substituting it back into the original equation.

$-104= 8x$

$-104= 8(-13)$

$-104= -104$

This checks out, so we know our answer is correct and x is equal to -13.

strojnjashka [21]3 years ago

3 0

Answer:

$- 104 = 8x \\ x = \frac{ - 104}{8} \\ x = - 13 \\ thank \: you$

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The length of a rectangle is five less than its width. The area of the rectangle is 84 square feet. Write a quadratic equation i

salantis [7]

Given:

The length of a rectangle is 5 less than its width.

The area of the rectangle is 84 square feet.

We need to determine the quadratic equation in standard form that represents the area of the rectangle.

Dimensions of the rectangle:

Let l denote the length of the rectangle.

Let w denote the width of the rectangle.

Since, it is given that the length is 5 less than its width, it can be written as,

$l=5-w$ and $w=w$

Area of the rectangle:

The area of the rectangle can be determined using the formula,

$A=length \times width$

Substituting A = 84, $l=5-w$ and $w=w$ , we get

$84=(5-w)\times w$

$84=5w-w^2$

Adding both sides of the equation by w², we have;

$w^2+84=5w$

Subtracting by 5w on both sides, we get;

$w^2-5w+84=0$

Thus, the quadratic equation in standard form for the area of the rectangle is $w^2-5w+84=0$

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3 years ago

Which equation represents the line that is perpendicular to and passes through (-12,6)?.

Evgesh-ka [11]

The equation that represents the line that is perpendicular is

3y + 5x = -42

The standard equation of a line in point-slope form is expressed as:

$y-y_1=m(x-x_1)$

m is the slope of the lne

(x1, y1) is any point on the line.

Given the equation y = 3/2x + 1, the slope of the line is 3/5

The slope of the line perpendicular is -5/3

Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

$y-6=-5/3(x-(-12))\\3(y-6)=-5(x+12)\\3y-18=-5x-60\\3y = -5x - 60 + 18\\3y + 5x = -42\\$

Hence the equation that represents the line that is perpendicular is

3y + 5x = -42

Learn more on equation of a line here:brainly.com/question/19417700

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2 years ago

$1.66 x 100 = ? I can't seem to find the correct answer and I must show my work

crimeas [40]

Answer:

166

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4

Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of (-9,-8) and (7,-4)

midpoint formula is

$\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}$

$\frac{-9+7}{2} ,\frac{-8+-4}{2}$

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

$slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}$

$slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}$

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4 and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

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3 years ago

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ValentinkaMS [17]

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