The first book can be any one of the 5.
For each of those . . .
The 2nd book can be any one of the remaining 4.
For each of those ...
The 3rd book can be any one of the remaining 3.
For each of those . . .
The 4th book can be either of the remaining 2.
For each of those . . .
The 5th book is the last one remaining.
Total number of ways to arrange the 5 books is
(5 · 4 · 3 · 2 · 1) = 120 .
Cross off alphabetically ascending (1 way), and alphabetically
descending (1 way), and you're left with (120 - 2) = 118 ways.
Adults = 9
Children = 2
Let x be the number of adults.
11-x is the number of children.
22x + 15(11-x) = 228
22x + 165 - 15x = 228
22x - 15x = 228 - 165
7x = 63
7x / 7 = 63 / 7
x = 9 number of adults.
11 - x = 11 - 9 = 2 number of children.
To check:
22x + 15(11-x) = 228
22(9) + 15(11-9) = 228
198 + 30 = 228
228 = 228
(not my answer btw)
Answer:
One pair of opposite sides are parallel and congruent
Step-by-step explanation:
As you can see, segment HE and GF are both marked as parallel and congruent
he volume of the solid under a surface
z
=
f
(
x
,
y
)
and above a region D is given by the formula
∫
∫
D
f
(
x
,
y
)
d
A
.
Here
f
(
x
,
y
)
=
6
x
y
. The inequalities that define the region D can be found by making a sketch of the triangle that lies in the
x
y
−
plane. The bounding equations of the triangle are found using the point-slope formula as
x
=
1
,
y
=
1
and
y
=
−
x
3
+
7
3
.
Here is a sketch of the triangle:
Intersecting Region
The inequalities that describe D are given by the sketch as:
1
≤
x
≤
4
and
1
≤
y
≤
−
x
3
+
7
3
.
Therefore, volume is
V
=
∫
4
1
∫
−
x
3
+
7
3
1
6
x
y
d
y
d
x
=
∫
4
1
6
x
[
y
2
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
y
2
]
−
x
3
+
7
3
1
d
x
=
3
∫
4
1
x
[
49
9
−
14
x
9
+
x
2
9
−
1
]
d
x
=
3
∫
4
1
40
x
9
−
14
x
2
9
+
x
3
9
d
x
=
3
[
40
x
2
18
−
14
x
3
27
+
x
4
36
]
4
1
=
3
[
(
640
18
−
896
27
+
256
36
)
−
(
40
18
−
14
27
+
1
36
)
]
=
23.25
.
Volume is
23.25
.