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zubka84 [21]
2 years ago
13

I need step by step please 3(x-2)^2+1=13

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
7 0

Answer:

x_{1} = 0. \:  \:  \:  x_{2} = 4

Step-by-step explanation:

3(x - 2)^{2}  + 1 = 3

3( {x}^{2}  - 4x + 4) + 1 = 13

{3x}^{2}  - 12x + 12 + 1 = 13

{3x}^{2}  - 12x + 13 = 13

{3x}^{2}  - 12x = 0

x \times (x - 4) = 0

x = 0

x - 4 = 0

\boxed{\green{x_{1} = 0. \:  \:  \:  x_{2} = 4}}

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Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
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The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

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 and (x2 , y2) are x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

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∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

∵ y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}

∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

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