<h3>Answer:</h3><h3> option D </h3><h3>Step-by-step explanation:</h3><h3> well looking at line <u>MQ and PT</u> they are bother parallel lines and parallel lines are equal that is they are the same making them concurrent </h3>
If x+y=k, then x=k-y. Substitute k-y for x in the other equation. So (k-y)-y=k. k-2y =k which means y has to be 0 (both k's subtract on both sides). -2y=0. The answer: (k,0). For the second part, get all the parts of the equations on both sides; (make both sides equal zero) 3x-4y-7 and 3x+2y+5. Then subtract. 3x-4y-7-(3x+2y+5) Make it equal to zero again and solve! :) -6y-12=0 -6y=12!! ta da!
Since the square roots are both six and cannot be simplified any more you just treat it like a normal subtraction problem
so -5 - 2= -7
so it would be -7√2
IIIIIIIIIIII DONTTTTT UNDERSTAND WHAT U HAVE TO DOOOOOOOOOOOO
Yes but it would result in a decimal.
