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Nutka1998 [239]
3 years ago
6

Find the length of RT R(12,7) T(6.-2) ​

Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0
05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2).
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Your answer should be B
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Determine the equation of the graph with the coordinates of (4, -1)
Anon25 [30]

Answer:

The required equation of the graph with the coordinates of (4, -1) will be:

  • y=\left(x-4\right)^2-1

The graph is also attached.

Step-by-step explanation:

Given the coordinates (4, -1)

If we put the coordinate values (4, -1) in the given equations, we determine that only y=\left(x-4\right)^2-1 is the valid equation as it satisfies the given coordinate value.

For example, putting  (4, -1) in the equation

y=\left(x-4\right)^2-1

\left(-1\right)=\left(4-4\right)^2-1

-1=\left(0\right)^2-1

-1=0-1

-1=-1

So, the equation y=\left(x-4\right)^2-1 is true for the coordinate values (4, -1).

Therefore, the required equation of the graph with the coordinates of (4, -1) will be:

  • y=\left(x-4\right)^2-1

Please check, the graph is also attached.

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larisa86 [58]

Answer:

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Step-by-step explanation:

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The following picture is a square pyramid where DE=8 cm and m∠ADE=60°.
Goryan [66]

<u>Given</u>:

The length of DE is 8 cm and the measure of ∠ADE is 60°.

We need to determine the surface area of the pyramid.

<u>Length of AD:</u>

The length of AD is given by

cos 60^{\circ}=\frac{FD}{8}

       4=FD

Length of AD = 8 cm

<u>Slant height:</u>

The slant height EF can be determined using the trigonometric ratio.

Thus, we have;

     sin \ 60^{\circ}=\frac{EF}{8}

sin \ 60^{\circ} \times 8=EF

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Thus, the slant height EF is 4√3

<u>Surface area of the square pyramid:</u>

The surface area of the square pyramid can be determined using the formula,

SA=Area \ of \ square + \frac{1}{2} (Perimeter \ of \ base ) (slant \ height)

Substituting the values, we have;

SA=8^2+\frac{1}{2}(8+8+8+8)(4 \sqrt{3})

SA=64+\frac{1}{2}(32)(4 \sqrt{3})

SA=64+(16)(4 \sqrt{3})

SA=64+64 \sqrt{3}

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Substituting √3 = 1.732 in the above expression, we have;

SA = 64 + 110.848

SA = 174.848

Rounding off to one decimal place, we get;

SA = 174.8

Thus, the area of the square pyramid is 174.8 cm²

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Because you can have a negative inside the absolute value so even if it is inside the absolute value of -3 will come out as 3.
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