When a wire is made smaller, the resistance increases. Which happens to the electric current?

2 answers:

7 0

Well, you can pretty much see it with this formula :

I = V/R

If the resistance (R) is increased, the amount of I will be increased.

so the answer would be : A. The current decreases

hope this helps

lys-0071 [83]4 years ago

3 0

Answer:

Option A

Explanation:

Ohm's law state that at constant temperature, the current flowing through the conductor is directly proportional to the potential difference applied across the conductor.

V = IR

Where, V is the potential difference, I is the electric current and R be the resistance of the conductor.

As resistance increases, current should be decreases to keep the potential difference constant.

In the question, as potential difference is same, so current is decreases.

You might be interested in

The velocity of a proton emerging from a Van de Graaff accelerator is 25.0% of the speed of light. What was the equivalent volta

LenaWriter [7]

Explanation:

Below is an attachment containing the solution.

8 0

4 years ago

Defind wave.then explain how vibrations,waves,and energy are related to sound

vagabundo [1.1K]

Waves are either transversal stereotypical pictures of waves or longitudinal it goes in rings waves are just different forms of vibration of any kind of energy

7 0

3 years ago

Read 2 more answers

protons in an atomic nucleus are typically 10-15 m apart. what is the electric force of repulsion between nuclear protons?

Aleonysh [2.5K]

230 Newton

Electric charge consists of two types i.e. positively electric charge and negatively electric charge.There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

F = electric force (N)

k = electric constant (N m² / C²)

q = electric charge (C)

r = distance between charges (m)

The value of k in a vacuum = 9 x 10⁹ (N m² / C²)

F = k(q1 q2)/ r^2

Distance between protons = d = 10⁻¹⁵ m

charge of proton = q = 1.6 × 10⁻¹⁹ C

Here q1=q2

electric force = F =230N

Coulomb's Law. Two protons in an atomic nucleus are typically separated by a distance of 2×10−15m. The electric repulsive force between the protons is huge, but the attractive nuclear force is even stronger and keeps the nucleus from bursting apart.

2 Nuclei and the Need for an Attractive Nuclear Force. The Coulomb force also acts within atomic nucleii, whose characteristic dimension is 10 m, which is called a fermi. There are two protons in a He nucleus, which repel each other because of the Coulomb force.

Find more about electric force of repulsion between nuclear protons

brainly.com/question/8404637

#SPJ4