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natta225 [31]
3 years ago
5

King arthurs knights fire a cannon from the top of the castle wall. the cannonball is fired at a speed of 50m/s and an angle of

30 degree. A cannonball that was accidentally dropped hits the moat below in 1.5s.
How far from the castle wall does the fired cannon hit the ground?
Physics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

Explanation:

initial height = 0.5*gt^2 = 0.5*9.8*1.5 = 7.35 m

now,

<em>x - x0 = ut + 1/2at^2 </em>

<em> </em>

<em>0 - 7.35 = 50sin(30)*t + (1/2)*(-9.8)*t^2 </em>

<em> </em>

<em>4.9t^2 - 25t - 7.35 = 0 </em>

solving this and taking only the positive value of t

t = (sqrt(76906)+250)/98 or <em>5.3808 secs</em>

a)

s = 50*cos(30 degree)*(sqrt(76906)+250)/98

<h2><u>s = 232.9959 m or 234 approx.</u></h2>
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