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Vesnalui [34]
1 year ago
14

If the car is traveling at a velocity of 15 m/s, what is the approximate centripetal acceleration of the car?.

Physics
1 answer:
BaLLatris [955]1 year ago
7 0

The vehicle's centripetal acceleration is equal to 22.5m/s²

Radius, r = 10 meter

Speed, V = 15 m/s

To ascertain the car's centripetal acceleration

A(c) = V²/R

We obtain the following when we enter the formula's parameters:

A(c) = 152/10

A(c) = 225/10

A(c) = 22.5m/s²

<h3>What is Centripetal acceleration ?</h3>

When an item moves in a circular route, one of its motion characteristics is centripetal acceleration. Any motion in a circle with an acceleration vector pointing in the direction of the circle's centre is referred to as centripetal acceleration.

  • Centripetal forces cause accelerations at the centripetal axis. With the exception of the Earth's rotation around the Sun, any satellite's circular motion around a celestial body is brought on by the centripetal force produced by their mutual gravitational pull.

Hence, Centripetal acceleration is

22.5 m/s²

Learn more about Centripetal acceleration here:

brainly.com/question/79801

#SPJ4

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a boy is standing 4 meter from a plane mirror how far and in what distance must te move so that he will be 4 meter from his imag
Alona [7]

Answer:

2 meters towards the mirror.

Explanation:

In a plane mirror the image distance is equal to the object distance. Therefore, by moving 2 meters towards the mirror, the boy reduces the distance between him and the mirror to two meters which is the object distance. The image distance is also 2 meters. add the two distances you will get four meters.

6 0
3 years ago
Consider the system consisting of two blocks connected by a rope and a pulley. The coefficient of static friction between the ra
RSB [31]

Answer:

1.2 kg

Explanation:

Let UP ramp be the positive direction

                                                  F = ma

   T     -   Wt ||      -         Ff            = m(0)

  mg   -  Μgsinθ -      μΜgcosθ    = 0

m(9.8) - 13sin35 - 0.36(13)cos35 = 0        

                                                 m = 13(sin35 + 0.36cos35) / 9.8

                                                 m = 1.15205... ≈ 1.2 kg

5 0
2 years ago
The pupil of an eagle’s eye has a diameter of 6.0 mm. Two field mice are separated by 0.010 m. From a distance of 185 m, the eag
max2010maxim [7]

Answer:

time is 5.973826 sec

Explanation:

Given data

diameter D =  6.0 mm  6× 10^{-3} m

separated d =  0.010 m

distance (dis) 185 m

speed s = 16 m/s

wavelength = 550 nm = 550  10^{-9} m

to find out

How much time passes

solution

we know that for resolution  we use Rayleigh's Criterion i.e

θ = 1.22 wavelength  / diameter  =  separated / distance 1

we calculate distance 1 by put value wavelength, diameter and   separated

distance 1  = diameter × separated / 1.22 wavelength

distance 1  = 6× 10^{-3} × 0.010   / 1.22 × 550 × 10^{-9}

distance 1 = 89.418778

so time will be i.e = distance (dis) - distance 1  / speed

time = ( 185 -  89.418778) / 16

time = 5.973826 sec

time is 5.973826 sec

4 0
3 years ago
What’s the stored energy related to positions of atoms within molecules
zepelin [54]

Cheimcal engery is related to positions of atoms within molecules..

8 0
3 years ago
After the elevator accelerates, then it moves at a constant speed of 6.0m/s, calculate the tension inthe cable.
Anon25 [30]

We know that

• The mass of the elevator is 5000 kg.

Let's draw a free-body diagram.

As you can observe, there are just two forces involved, the weight of the elevator and the tension force. Let's use Newton's Second Law.

\begin{gathered} \Sigma F_y=ma_y \\ T-W=ma_y \end{gathered}

But, W = mg = 5000kg*9.8m/s^2 = 49,000 N, and m = 5000 kg, a = 0 (because the speed is constant).

\begin{gathered} T-49,000N=5000\operatorname{kg}\cdot0 \\ T=49,000N \end{gathered}<h2>Therefore, the tension in the cable is 49,000 N.</h2>

3 0
1 year ago
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