Answer:
a = 6 [m/s^2]
Explanation:
In order to calculate the acceleration of the skier, the following expression of kinematics must be used:
a = (v)/t
where:
v = velocity = 24 [m/s]
t = time = 4 [s]
a = 24/4 = 6 [m/s^2]
Explanation:
1) N₂ + O₂ → 2 NO
Kc = [NO]² / ([N₂] [O₂])
Set up an ICE table:
Plug into the equilibrium equation and solve for x.
1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))
1.00×10⁻⁵ = (2x)² / (0.114 − x)²
√(1.00×10⁻⁵) = 2x / (0.114 − x)
0.00316 = 2x / (0.114 − x)
0.00361 − 0.00316x = 2x
0.00361 = 2.00316x
x = 0.00018
The volume is 1.00 L, so the concentrations at equilibrium are:
[N₂] = 0.114 − x = 0.11382
[O₂] = 0.114 − x = 0.11382
[NO] = 2x = 0.00036
2(a) Cl₂ → 2 Cl
Kc = [Cl]² / [Cl₂]
1.2×10⁻⁷ = (2x)² / (2 − x)
1.2×10⁻⁷ (2 − x) = 4x²
2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²
2.4×10⁻⁷ ≈ 4x²
x² ≈ 6×10⁻⁸
x ≈ 0.000245
2x ≈ 0.00049
2(b) F₂ → 2 F
Kc = [F]² / [F₂]
1.2×10⁻⁴ = (2x)² / (2 − x)
1.2×10⁻⁴ (2 − x) = 4x²
2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²
2.4×10⁻⁴ ≈ 4x²
x² ≈ 6×10⁻⁵
x ≈ 0.00775
2x ≈ 0.0155
F₂ dissociates more, so Cl₂ is more stable at 1000 K.
The law of reflection states that when a ray of light reflects off a surface, the <em>angle of incidence is equal to the angle of reflection</em>.
In this question, the light ray passes from air to water, an optically denser medium.
Imagine drawing a line to representing the boundary between two mediums. Now imagine drawing a line perpendicular to that boundary line marking where the light ray intersects the boundary line. This second line is called the normal. Whenever a light ray passes into a denser medium with a nonzero angle of incidence, the ray will bend towards the normal, making the <em>angle of refraction smaller than the angle of incidence</em>.
Choice A