Answer:
a) w = 9.599 10⁴ rad / s
, b) v = 3.35 10¹⁶ m / s
, c) a = 3.22 10²¹ m / s²
Explanation:
For this exercise we must use the relation of angular kinematics
a) angular velocity, the distance remembered in orbit between time (period)
w = 2π r / T
w = 2 π 3.59 10¹¹ / 2.35 10⁷
w = 9.599 10⁴ rad / s
b) linear and angular velocity are related by the equation
v = w r
v = 9,599 10⁴ 3.49 10¹¹
v = 3.35 10¹⁶ m / s
c) the centripetal acceleration is
a = v² / r = w² r
a = (9,599 10⁴)² 3.49 10¹¹
a = 3.22 10²¹ m / s²
Answer:
Coulomb Force
Explanation:
Coulomb force, also called electrostatic force or Coulomb interaction, attraction or repulsion of particles or objects because of their electric charge.
Answer:
W = 7000 J
Explanation:
To solve this problem we use that the speed of the bicycle is constant, therefore its acceleration is zero
F -fr = 0
F = fr
where F is the force applied by the child
Work is defined by
W = F. x
W = F x cos θ
in this case the child's force is parallel to the movement, therefore the angle is zero and cos 0 = 1
let's calculate
W = 35 200
W = 7000 J
Answer:
x ≈ 56 m
Explanation:
vertical initial velocity =
= 25 m/s* sin(30°)= 12.5 m/s
height = h
t- time is found solving quadratic equation.
horizontal velocity = 
Horizontal velocity is constant, so distance 
Answer:
10.8s
Explanation:
Given parameters:
Force on the car = 3250N
Distance = 35m
Power = 11375W
Unknown:
Time taken = ?
Solution:
To solve this problem;
Power is the rate at which work is done
Power = 
Work done = force x distance = 3250 x 35 = 123200J
Now;
11375 = 
11375t = 123200
t = 10.8s
