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algol [13]
3 years ago
9

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

ad. Exceptions are allowed, but they want the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages. (a-1) Find the test statistic. (Round your answer to 4 decimal places.) The test statistic (a-2) At the .01 level of significance, is the true mean greater than 10
Mathematics
1 answer:
borishaifa [10]3 years ago
7 0

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ ≤ 10

For the alternative hypothesis,

µ > 10

The inequality sign indicates that It is a right tailed.

Since the population standard deviation is not given, the distribution is a student's t.

Since n = 35,

Degrees of freedom, df = n - 1 = 35 - 1 = 34

t = (x - µ)/(s/√n)

Where

x = sample mean = 14.44

µ = population mean = 10

s = samples standard deviation = 4.45

t = (14.44 - 10)/(4.45/√35) = 5.9

We would determine the p value using the t test calculator. It becomes

p < 0.00001

Since alpha, 0.01 > than the p value, then we would reject the null hypothesis. Therefore, At a 1% level of significance, we can conclude that the true mean is greater than 10.

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Graph the line that passes through the points (-4, -1) and (-4, 2) and determine the equation of the line.​
My name is Ann [436]

Answer:

X = -4

Step-by-step explanation:

7 0
3 years ago
Sunshine High School claims that 72% of its students complete their homework on a daily basis. Ms. Carter surveyed 80 students a
Ulleksa [173]

Answer: z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

Step-by-step explanation:

let p be the population proportion of students complete their homework on a daily basis.

As per given , we have

p= 0.72

sample size : n= 80

Sample proportion : \hat{p}=0.60

Test statistic for proportion:

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(1-0.72)}{80}}}

i.e.

z=\dfrac{0.60-0.72}{\sqrt{\dfrac{0.72(0.28)}{80}}}

That is , z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

6 0
3 years ago
Let x be the amount of time (in hours) the wait is to get a table at a restaurant. Suppose the cdf is represented by f(x)=⎧⎩⎨⎪⎪⎪
sattari [20]

Option a is correct. The calculated answer is 0.150

<h3>How to get the value using the cdf</h3>

In order to get  P(0.5 ≤ X ≤ 1.5).

This can be rewritten as

p = 0.5

and P = 1.5

We have the equation as

\frac{1}{16} x^{2}

This would be written as

1.5²/16 - 0.5²/16

= 0.1406 - 0.015625

= 0.124975

This is approximately 0.1250

Read more on cdf here:

brainly.com/question/19884447

#SPJ1

<h3>complete question</h3>

Use the cdf to determine P(0.5 ≤ X ≤ 1.5).

a) 0.1250

b) 0.0339

c) 0.1406

d) 0.0677

e) 0.8750

f) None of the above

4 0
2 years ago
A bag contains 5 black marbles, 9 white marbles, and 2 red marbles. One marble is to be chosen at random. What is the probabilit
Ugo [173]
5 + 9 + 2 = 16 
We choose one of sixteen, =>
A. 1/16
5 0
3 years ago
Read 2 more answers
Dylan has a 32-ounce coffee.He drinks 4 ounces. What is the percentage of ounces left of his coffee?
Semenov [28]

32 \div 100 = 3.125 \\  \\ 3.125 \times 4 = 12.5 \\  \\ 100 - 12.5 = 87.5 \\  \\ 87.5
8 0
3 years ago
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