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Svetlanka [38]
3 years ago
14

− 4 x −4x y = y= x − 5 x−5 please answer with a short answer, if not its ok.

Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

x=5/4y

Step-by-step explanation:

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Simplify (32)2<br> A) 9 <br> B) 18 <br> C) 27 <br> D) 81
Amiraneli [1.4K]

Answer:

D)81

Step-by-step explanation:

5 0
3 years ago
A sector of a circle has central angle 120 degrees and arc length 10π
zzz [600]

Answer:

<h2>the radius = 15 cm</h2>

Step-by-step explanation:

let r be the radius of the circle.

→ We know that in circle , the length of an arc

and the corresponding central angle are proportional.

180 corresponds to πr

120 corresponds to 10π

Then

\frac{\uppi r}{180} =\frac{10\uppi }{120}

\Longrightarrow r=\frac{180\times 10\pi }{120\pi } =\frac{180}{12} =15

7 0
2 years ago
Stuck!!! Pleaseeeeee helpp
Reil [10]

Answer:

w=4

Step-by-step explanation:

since JK and IH equals each other you do:

9w-3= w+29

-w      -w

8w-3=29

    +3  +3

8w=32

32/8=4

4 1
3 years ago
Two dice are
RideAnS [48]

Answer:

Step-by-step explanation:

Remark

Two results are divisible by 5.

The two are 5 and 10.

There are 36 possible outcomes when throwing 2 dice

Five

You can throw a 5 four different ways

4 - 1

1 - 4

2 - 3

3 - 2

Probability: 4/36

Ten

Ten can be thrown 3 different ways

5 - 5

6 - 4

4- 6

Probability : 3/36

Answer

The probability of a 5 or a 10 = 4/36 + 3/36 = 7/36

If you mean  something else, leave a note in the comment and I'll get back to this. Please leave something specific. It's wrong doesn't help me.

7 0
3 years ago
What to do if quadratic equation has a negative spuare root?
alex41 [277]

If the negative square root is found to be one of your solutions, then that is indicative of a pair of imaginary roots (the imaginary i). According to the conjugate rule, if you have one solution that is imaginary, you will have another but with the opposite sign. For example, if a solution to a quadratic is found to be 2 - i, then its conjugate, 2 + i is also a solution. They will ALWAYS go in pairs. Same thing with radical solutions. If one solution is found to be 3+\sqrt{5}

then 3-\sqrt{5} will also be a solution.

3 0
4 years ago
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