Answer:
The fate of glucose-6-phosphate,glycolytic intermediates and pentose phosphate pathways are described below
Explanation:
Fate of Glucose -6-phosphate
Glucose-6-phosphate undergo dephosphorylation to form glucose when there is an increase demand of glucose in the body.
Glucose-6-phosphate enters into pentose phosphate pathway to synthesize ribose-5-phosphate which is used during denovo pathway of purine nucleotide biosynthesis.
Fate of glycolytic intermediates
Glyceraldehyde-3-phosphate is an important intermediate of glycolysis.The glyceraldehyde-3-phosphate act as a precursor during lipogenesis that deals with the biosynthesis of triacylglycerol.
Fate of pentose phosphate pathway intermediates
Ribose-5-phosphate and NADPH are the important intermediates of pentone phosphate pathway.
Ribose-5-phosphate act as a substrate molecule during the denovo biosynthesis pathway of purine nucleotides.
NADPH act as a reducing agent during fatty acid biosynthesis process.
A cell wall is a permeable layer found in plant cells which acts as a membrane through which water molecules can pass through while animal cells do not have cell walls.. they just have a cell membrane which is selectively permeable to some chemicals or substances.. water does not move from the region of higher to lower concentration in animal cells
In short, plant cells have cell walls that allow osmosis while animal cells do not have cell walls for osmosis to take place
hope it helps you :)
Instead in our hands... something else happens rills or groove shaped lines are formed in our fingers.. it is an adaptation for our body to provide for some friction in water...
Answer:
The correct answer is C) 1 L of 1.0 M NaCl
Explanation:
NaCl is a ionic compound so it dissociates in water into Na⁺ and Cl⁻ ions. Glucose is a covalent solute so it does not dissociates into ions. So, when we dissolve NaCl we have twice the amount of particles in solution in comparison with glucose. According to this:
A) and B) are solutions with the same concentration (0.5 M) but NaCl solution will have more solute particles than glucose.
C) and D) are solutions with more solute amount because they are more concentrated (1 M), but NaCl solution will have more solute particles than glucose solution ( 1 mol of Na⁺ ions + 1 mol of Cl⁻ ions).
The solution with the greatest solute particle number is C).
In hemophilia A it’s caused by a mutation in the gene for factor VIII. Hemophilia B is a result in a deficiency in factor IX due to a mutation in its corresponding gene.
In both cases, it is a mutation in the DNA (the macromolecule).
The correct answer is signal transduction.
Signal transduction also called cell signaling refers to the conduction of molecular signals from the external of the cell to its internal. The signals perceived by the cells must be conducted efficiently into the cell to make sure an effective response. This step is stimulated by cell-surface receptors.
There are three phases in the procedure of communication or cell signaling, that is, reception, transduction, and response.
