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yanalaym [24]
3 years ago
6

A polynomial function of degree 4 with real coefficients could have -3, 1+i, 1-i, and -3,7i as its zeros. true or false

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Using complex numbers concepts, it is found that the statement is false.

When a complex number is a root of a polynomial function, it's conjugate also has to be.

  • A complex number has the format a + bi, and it's conjugate is a - bi.

In this problem:

  • Real root -3.
  • Complex-conjugate roots 1 + i and 1 - i.
  • Complex root -3 + 7i.

The conjugate of -3 + 7i also has to be a root, which would make the polynomial of the 5th degree, as it would have 5 roots, thus, the statement is false.

A similar problem is given at brainly.com/question/24450834

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Answer:

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Step-by-step explanation:

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An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh
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Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

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In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0
2 years ago
Two step equation<br><br> a - 10/3 = -4
cricket20 [7]

a=-2

a-10/3=-4

a-10=-4*3

a-10=-12

a=-12+10

a=-2 is the best answer

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2 years ago
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