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yanalaym [24]
3 years ago
6

A polynomial function of degree 4 with real coefficients could have -3, 1+i, 1-i, and -3,7i as its zeros. true or false

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
5 0

Using complex numbers concepts, it is found that the statement is false.

When a complex number is a root of a polynomial function, it's conjugate also has to be.

  • A complex number has the format a + bi, and it's conjugate is a - bi.

In this problem:

  • Real root -3.
  • Complex-conjugate roots 1 + i and 1 - i.
  • Complex root -3 + 7i.

The conjugate of -3 + 7i also has to be a root, which would make the polynomial of the 5th degree, as it would have 5 roots, thus, the statement is false.

A similar problem is given at brainly.com/question/24450834

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In a statistics mid-term exam graded out of 100 points, the distribution of the exam scores was bi-modal with a mean of 70 point
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Answer:

Step-by-step explanation:

Assuming a normal distribution for the distribution of the points scored by students in the exam, the formula for normal distribution is expressed as

z = (x - u)/s

Where

x = points scored by students

u = mean score

s = standard deviation

From the information given,

u = 70 points

s = 10.

We want to find the probability of students scored between 40 points and 100 points. It is expressed as

P(40 lesser than x lesser than or equal to 100)

For x = 40,

z = (40 - 70)/10 =-3.0

Looking at the normal distribution table, the corresponding z score is 0.0135

For x = 100,

z = (100 - 70)/10 =3.0

Looking at the normal distribution table, the corresponding z score is 0.99865

P(40 lesser than x lesser than or equal to 100) = 0.99865 - 0.0135 = 0.98515

The percentage of students scored between 40 points and 100 points will be 0.986 × 100 = 98.4%

4 0
3 years ago
Read 2 more answers
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