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Anastasy [175]
3 years ago
10

What is the volume of a substance that has a density of 13.6 g/cm and a mass of 3.0 g?

Chemistry
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

\boxed {\boxed {\sf v \approx  0.22 \ cm^3}}

Explanation:

We are asked to find the volume of a substance.

We are given the density and the mass. The density of a substance is its mass per unit volume. The formula for calculating density is:

\rho= \frac{m}{v}

We know the density of the substance is 13.6 grams per cubic centimeter and the mass is 3.0 grams.

  • ρ= 13.6 g/cm³
  • m= 3.0 g

Substitute these values into the formula.

13.6 \ g/cm^3= \frac{3.0 \ g }{v}

We are solving for the volume, so we must isolate the variable v. First, cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.

\frac{13.6 \ g/cm^3}{1}= \frac{3.0 \ g }{v}

13.6 \ g/cm^3 *v =3.0 \ g *1

Multiply on the right side of the equation.

13.6 \ g/cm^3 *v =3.0 \ g

The variable is being multiplied by 13.6 grams per cubic centimeters. The inverse operation of multiplication is division, so we divide both sides of the equation by 13.6 g/cm².

\frac {13.6 \ g/cm^3 *v}{13.6 \ g/cm^3} =\frac{3.0 \ g }{13.6 \ g/cm^3}

v =\frac{3.0 \ g }{13.6 \ g/cm^3}

The units of grams cancel.

v =\frac{3.0  }{13.6 \ cm^3}

v= 0.2205882353 \ cm^3

The original measurement of density has 3 significant figures and the measurement of mass has 2. Our answer must have the least number of sig figs, which is 2. For the number we found, that is the hundredth place. The 0 in the thousandth place tells us to leave the 2 in the hundredth place.

v \approx 0.22 \ cm^3

The volume of the substance is approximately <u>0.22 cubic centimeters.</u>

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A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t
gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

C_{1} V_{1} = C_{2} V_{2}, where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

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Performing division on Right Hand Side

C_{2} = 1.4%

Hence, the final concentration is 1.4%.

Learn more about concentration -

brainly.com/question/17206790

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The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

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Answer:

ℂ

Explanation:

ℂ

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Given the balanced equation:
Svet_ta [14]
Is there any answer choices before i get started on working out the problem
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