<h3>
Answer:</h3>
89.88° C
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of gold cylinder as 75 g
- specific heat of gold is 0.129 J/g°C
- Initial temperature of gold cylinder is 65°C
- Mass of water is 500 g
- Initial temperature of water is 90 °C
We are required to calculate the final temperature;
- We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>
Assuming the final temperature is X° C
Then; ΔT = (X-65)°C
Therefore;
Q = 75 g × 0.129 J/g°C × (X-65)°C
= 9.675X - 628.875 Joules
<h3>Step 2: Calculate the quantity of heat released by water</h3>
Taking the final temperature as X° C
Change in temperature, ΔT = (90 - X)° C
Specific heat capacity of water is 4.184 J/g°C
Therefore;
Q = 500 g × 4.184 J/g°C × (90 - X)° C
= 188,280 -2092X joules
<h3>Step 3: Calculate the final temperature, X°C</h3>
we know that the heat gained by gold cylinder is equal to the heat released by water.
9.675X - 628.875 Joules = 188,280 -2092X joules
2101.675 X = 188908.875
X = 89.88° C
Thus, the final temperature is 89.88° C
We are going to use Avogadro's constant to calculate how many molecules of
carbons dioxide exist in lungs:
when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in
CO2 when the number of moles is 5 x 10^-2
number of molecules = moles of CO2 * Avogadro's number
= 5 x 10^-2 * 6.02 x 10^23
= 3 x 10^22 molecules
∴ There are 3 x 10^22 molecules in CO2 exist in lungs
Because metallic bonding is non-localized, and extends throughout the metallic lattice. Metal nuclei can move with respect to other metal nuclei without disrupting the forces of attraction.
Answer:
1023.75mmHg
Explanation:
V1 = 3.5L
P1 = 585mmHg
V2 = 2.0L
P2 = ?
To solve this question, we'll require the use of Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature is kept constant.
Mathematically,
V = kP, k = PV
P1 × V1 = P2 × V2 = P3 × V3 = .......= Pn × Vn
P1 × V1 = P2 × V2
Solve for P2,
P2 = (P1 × V1) / V2
P2 = (585 × 3.5) / 2.0
P2 = 2047.5 / 2.0
P2 = 1023.75mmHg
The final pressure of the gas is 1023.75mmHg
