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IRINA_888 [86]
3 years ago
6

For alpha decay to cause a loss in mass, such as that in the uranium 238 conversion to thorium 234, what must the atomic weight

of the alpha particle be?
Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Explanation:

Reaction equation showing alpha decay in Uranium-238 is as follows.

    ^{238}_{92}U \rightarrow ^{234}_{90}Th + ^{4}_{2}He

It is known that an alpha particle is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is ^{4}_{2}\alpha.

As atomic mass or weight is the sum of total number of protons and neutrons present in an atom.

Hence, the atomic weight of the alpha particle is (2 + 2) = 4.

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G The chemicals above are dissolved in water to make a solution. Which ones will conduct electricity
tatiyna

Answer:

This question is incomplete

Explanation:

Although, the question above is incomplete, however the correct option can be deduced from the explanation below.

Compounds/chemicals that dissolve in water to conduct electricity are Ionic/electrovalent compounds. Ionic compounds/salts are compounds that are held together by ionic/electrovalent bond. These compounds dissociate in water to form ions; the dissociated ions formed are the carriers of electric charges hence enabling the salt solution conduct electricity. Examples of these electrovalent/ionic compounds include NaCl, CaCl₂, CsF and MgO.

NOTE: Identify the ionic/electrovalent compounds in the options (from the completed question) to get your answer.

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3 years ago
Which type of energy is associated with the random motion of atoms and molecules in the sample of air?
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Answer - Thermal energy
7 0
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Convection is said to occur in _______ , which includes liquids and gases.
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4 0
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8 0
3 years ago
Calculate the AHrxn from the AH of formation for the following reaction. C2H4(g) + 302(g) 2C02(g) + 2H20(1). Formation AH values
RSB [31]

Answer

A. -1305 kJ

Explanation

Given:

Equation: C2H4(g) + 302(g) ---- > 2C02(g) + 2H20(l).

Formation ΔH values:

​​for C2H4(g) = 52.30 kJ/mol,

for 02(g) = 0 kJ/mol,

for CO2(g) = -393.5 kJ/mol, and

for H20(1) = -285.8kJ/mol.

What to find:

The ΔHrxn from the ΔH of formation for the given reaction.

Step-by-step solution:

ΔHrxn = (Sum of ΔH formation for the product) - (Sum of ΔH formation for the reactants).

ΔHrxn = (ΔH for 2CO2(g) + ΔH for 2H2O(l)) + (ΔH for C2H4(g) + ΔH for 3O2(g))

ΔHrxn = [(2 x -393.5) + (2 x -285.8)] + [52.30 + (3 x 0)]

ΔHrxn =(-787.0 - 571.6) + (52.30 + 0)

ΔHrxn = -1358.6 + 52.30

ΔHrxn = -1306.3 kJ

so the closest answer is A. -1305 kJ

4 0
1 year ago
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