It is a ,d and c just make sure tho
Answer:
Elemental S reacts with O2 to form SO3 according to the reaction 2S+3O2→2SO3 Part B: What is the theoretical yield of SO3 produced by the quantities described in Part A? Express your answer numerically in grams.
Part A: 1.88x10^23 O2 molecules are needed to react with 6.67 g of S.
We address the equation...
S
(
s
)
+
3
2
O
2
(
g
)
→
S
O
3
(
g
)
Explanation:
The question specifies that we got
1.88
×
10
23
dioxygen molecules
...i.e. a molar quantity of...
1.88
×
10
23
⋅
molecules
6.022
×
10
23
⋅
molecules
⋅
m
o
l
−
1
=
0.312
⋅
m
o
l
...
But we gots with respect to sulfur,
6.67
⋅
g
32.06
⋅
g
⋅
m
o
l
−
1
=
0.208
⋅
m
o
l
...
And a bit of arithmetic later, we establish that we got stoichiometric quantities of dioxygen, and sulfur….in the reaction we produce a mass of ………..
0.208
⋅
m
o
l
×
80.07
⋅
g
⋅
m
o
l
−
1
=
16.65
⋅
g
.
Note that when
sulfur trioxide
is made industrially (and this a very important commodity chemical), sulfur is oxidized to
S
O
2
, and this is then oxidized up to
S
O
3
with some catalysis...
S
O
2
(
g
)
+
1
2
O
2
(
g
)
V
2
O
5
−−→
S
O
3
(
g
)
S
O
3
(
g
)
+
H
2
O
(
l
)
→
H
2
S
O
4
(
a
q
)
sulfuric acid
The industrial sulfur cycle must be a dirty, smelly, unfriendly process. The process is undoubtedly necessary to support our civilization....
Answer:
Explanation:
A testable question is the one which can be answered using experiment and research. A non-testable question is the one which cannot be answered using experimental trials.
Example:
Non-testable: Which is more better ice-cream or chips?
Testable: Which is more better nutritionally ice-cream or chips?
Here, in the non-testable question no parameter was given for comparision and analysis hence, it cannot be tested experimentally. Whereas, in the testable question nutritional quality is to be compared between the two food items.
Answer:
Explanation:
The final net force will be in the Z- direction. Let's find out the z component of the force on the differential volume of charge is:
df = dqEcosθz
dq = ρdV = dr.sinθdθdΦ
integrate it over half ball,
.sinθcosθdθdΦ.( these are part of the integral, i was unable to write it in equation format).
= sinθcosθdθ
=