For this case we have that by definition, the area of a circular sector is given by:
![A = \frac {\alpha}{360}\pi r^2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%20%7B%5Calpha%7D%7B360%7D%5Cpi%20r%5E2)
Where,
- <em>r: radius of the circle
</em>
- <em>α: Central angle
</em>
Therefore, replacing values we have:
![A = \frac {30} {360} \pi (6) ^ 2\\A = 9.42 ft ^ 2](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%20%7B30%7D%20%7B360%7D%20%5Cpi%20%286%29%20%5E%202%5C%5CA%20%3D%209.42%20ft%20%5E%202)
Answer:
The area of a sector bounded by a 30 ° arc is:
![A = 9.42 ft ^ 2](https://tex.z-dn.net/?f=A%20%3D%209.42%20ft%20%5E%202)
Answer: The probability that a randomly selected adult doesn’t regularly consume at least one of these two products is 30%
Be:
A: Adults regularly consume coffee
B: Adults regularly consume carbonated soda
C: Adults doesn't regularly consume at leas one of these two products.
55% of all adults regularly consume coffee→P(A)=55%=55/100→P(A)=0.55
45% regularly consume carbonated soda→P(B)=45%=45/100→P(B)=0.45
70% regularly consume at least one of these two products→P(A U B)=70%=70/100→P(A U B)=0.70
a) What is the probability that a randomly selected adult regularly consumes both coffee and soda?
P(A ∩ B)=?
P(A U B)=P(A) + P(B) - P(A ∩ B)
Replacing P(A U B)=0.70; P(A)=0.55; and P(B)=0.45 in the equation above:
0.70=0.55 + 0.45 - P(A ∩ B)→
0.70=1.00 - P(A ∩ B)
Solving for P(A ∩ B): Subtracting 1.00 both sides of the equation:
0.70-1.00=1.00 - P(A ∩ B) -1.00→
-0.30 = - P(A ∩ B)
Multiplying both sides of the equation by (-1):
(-1)(-0.30) = (-1)[ - P(A ∩ B)]→
0.30 = P(A ∩ B)→
P(A ∩ B) =0.30→
P(A ∩ B) = (0.30)*100%→
P(A ∩ B) = 30%
Answer: The probability that a randomly selected adult regularly consumes both coffee and soda is 70%
b. What is the probability that a randomly selected adult doesn’t regularly consume at least one of these two products?
P(C)=?
P(A U B) + P(C)=1
Replacing P(A U B)= 0.70 in the equation above:
0.70+P(C)=1
Solving for P(C). Subtracting 0.70 both sides of the equation:
0.70+P(C)-0.70=1-0.70→
P(C)=0.30→
P(C)=(0.30)*100%→
P(C)=30%
Answer: The probability that a randomly selected adult doesn’t regularly consume at least one of these two products is 30%
Answer:
Im confused
Step-by-step explanation:
Answer:147.57
Step-by-step explanation:
Answer:
y = 9,958(0.972)^t
Step-by-step explanation:
From point to point, the difference in days is always constant (10 days), but the difference between estimated number of bees is not constant.
10000 - 7500 = 2500
7500 - 5600 = 1900
5600 - 4200 = 1600
4200 - 3200 = 1000
3200 - 2400 = 800
Therefore, the data don't fit a line.
From the other two options:
y = 9,958(0.972)^t
y = 0.972(9,958)^t
only the first one has sense, because its initial amount of bees is 9,958 (near to 10,000) and in the second option is 0.972.