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Viefleur [7K]
2 years ago
7

Help thanksss. its mutiple choice

Mathematics
1 answer:
Flura [38]2 years ago
3 0

Answer:

Points C,D, E and F are coplanar.

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I need help. line wx is parallel to line yz
Oksana_A [137]

Answer:

45

Step-by-step explanation:

<ABY=<ZBY(VERTICAL ANGLES)

SO.

3x-5=2x+40

3x-2x=40+5

x=45

3 0
3 years ago
Read 2 more answers
Determine whether each question below is a statistical question. Write "yes" or "no" in the spaces provided.
nikdorinn [45]

Answer:

a yes

b no

c no

d yes

e yes

f no

7 0
3 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
I WILL GIVE BRAINLIEST. 1/2 of the problems on a 20-question test are algebra and one-half are geometry. Determine the probabili
aksik [14]

9514 1404 393

Answer:

  0.344

Step-by-step explanation:

There are 20C10 = 184,756 ways to choose 10 problems at random from a list of 20.

There are 10C5 = 252 ways to choose 5 of the 10 algebra problems, and the same number of ways to choose 5 of the 10 geometry problems. Then there are 252² = 63,504 ways to choose 5 problems each of algebra and geometry.

The probability of choosing 5 problems in each category is ...

  63504/184756 ≈ 0.344

6 0
3 years ago
NEED THE CORRECT ANSWER ASAP, PLEASE HELP!!! Drag and drop the expressions into the boxes to correctly complete the proof of the
belka [17]

Answer:

See attached

Step-by-step explanation:

The proof is attached

4 0
3 years ago
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