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2 years ago

Help thanksss. its mutiple choice

Mathematics

1 answer:

Flura [38]2 years ago

3 0

Answer:

Points C,D, E and F are coplanar.

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Which graph shows a system of equations with no solutions? On a coordinate plane, the graphs of 2 circles are shown. Both circle

daser333 [38]

Answer:

1st Graph: 2 circles are shown

Step-by-step explanation:

In order to have a solution set, the 2 graphs need to intersect each other. All the graphs but the 2 circles intersect and have a solution. Therefore, our answer is the 1st Graph.

8 0

2 years ago

Read 2 more answers

Evaluate v(x) = 14-3x when x=-3, 0 and 4.

PtichkaEL [24]

Answer:

$v(-3)=23\\v(0)=14\\v(4)=2$

Step-by-step explanation:

$v(x)=14-3x$

$v(-3)=14-3(-3)\\\\v(-3)=14-(-9)\\\\v(-3)=23$

$v(0)=14-3(0)\\\\v(0)=14-0\\\\v(0)=14$

$v(4)=14-3(4)\\\\v(4)=14-12\\\\v(4)=2$

5 0

2 years ago

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Math SAT: Suppose the national mean SAT score in mathematics was 510. In a random sample of 50 graduates from Stevens High, the

sukhopar [10]

Answer:

Mean SAT score for Stevens High graduates are not the same as the national average.

Step-by-step explanation:

We are given the following information in question:

Population mean, μ = 510

Sample mean, $\bar{x}$ = 501

Sample size, n = 50

Alpha, α = 0.10

Sample standard deviation, s = 30

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 510\\H_A: \mu \neq 510$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have,

$t_{stat} = \displaystyle\frac{501 - 510}{\frac{30}{\sqrt{49}} } = -2.1$ Now,

$t_{critical} \text{ at 0.10 level of significance, 49 degree of freedom } = \pm 1.6765$ Since,

$t_{stat} < t_{critical}$

We reject the null hypothesis and fail to accept it.

We accept the alternate hypothesis and mean SAT score for Stevens High graduates are not the same as the national average.

3 0

2 years ago

Someone help me please

galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: $a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }$

Hence, ∛27 = $27^{(\frac{1}{3})}$

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

$\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}$

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0

2 years ago

Read 2 more answers

Need help with this function problem

kotykmax [81]

Answer:

see attached

Step-by-step explanation:

To find the inverse function, solve ...

x = f(y)

x = (y^7)/7 -4 . . . . . . . use the definition of f(x)

x +4 = (y^7)/7 . . . . . . add 4

7(x +4) = y^7 . . . . . . multiply by 7

(7(x +4))^(1/7) = y . . take the 7th root

The inverse function is the one shown in the attachment.

4 0

2 years ago