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scoundrel [369]
3 years ago
15

If a car travels 640 miles in 11 hours, what is the average rate (speed) of the car? A) 0.017 mph B) 17.12 mph C) 58.18 mph D) 6

2.9 mph
Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
640 divided by 11 equals 58.18 mph
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7

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Write the equation of the line that passes through (3, 4) and (2, –1) in slope-intercept form.
Inessa [10]
The equation of the line is
y = 5x-11
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ohan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. which explains whether his solut
klio [65]
-2 | 8-x| - 6 = -12...add 6 to both sides
-2 |8-x| = -12 + 6
-2 |8-x| = - 6...divide both sides by -2
|8-x| = -6/-2
|8-x| = 3

8 - x = -3          -(8 - x) = -3
-x = -3-8           -8 + x = -3
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not correct.....sign error
5 0
3 years ago
A JET TRAVELS 460 MILES IN 2 HOURS?
Tanzania [10]

Find how fast it travels in one hour:

460 miles / 2 hours = 230 miles per hour.

A) Multiply the speed per hour by the number of hours:

230 x 8 = 1840 miles in 8  hours.

B) 230 x 20 = 4,600 miles in 20 hours.

C) 460 miles /  2 hours = 230 miles per hour.

8 0
3 years ago
Read 2 more answers
25 (a square) - 4 (b square) + 28bc - 49 (c square)
LUCKY_DIMON [66]

Answer:

(5a - [2b - 7c]) and (5a + [2b + 7c])

Step-by-step explanation:

Factor 25a^2 - 4b^2 + 28bc - 49c^2.

Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable.  Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:

- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or

                                        -(2b - 7c)^2.

Thus, the original  25a^2 - 4b^2 + 28bc - 49c^2  looks like:

                               [5a]^2 - [2b - 7c]^2

Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b).  Applying this pattern to the problem at hand, we conclude:

Thus,   [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])

8 0
3 years ago
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