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alekssr [168]
3 years ago
6

Find the coordinates of P that partitions segment AB , where A (2,3) and B (14,9), so that AP:PB is a 1:2 ratio. Also, find the

coordinate of a point M that bisects segment AB​

Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

For Point P, you need to recognize that a 1:2 ratio means that AP will be 1/3 of AB and PB will be 2/3 of AB.

So you need to find the change in the x-values, 14-2 = 12, and then add 1/3 of that change to the x-value of A.

Then you need to find the change in the y-values, 9-3 = 6, and then add 1/3 of that change to the y-value of A.

For the bisector, that's another way to say you'll split AB into two even pieces.  For this, it's the same as what we just did, but you need to find 1/2 of the two respective changes (1/2 of the x-change and 1/2 the y-change).

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Step-by-step explanation:

From the given question it appears that (n-1) is in the numerator's place, if it is so, then let us solve it.

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Given that a:b=8:5 b:c=3:4 find the ratio a:b:c
olga55 [171]
A:b = 8:5 b:c = 3:4
since both sides have b. make b the same. multiply the left by the right side b value of 3 and multiply the right  by the left side b value of 5.
3(a:b)  and 5(b:c)
3 (8:5) and 5(3:4)
24:15          15:20
now that both sides have the same b value
a:b:c = 24:15:20

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Answer:

5gx

Step-by-step explanation:

all you have to do is  simplify it  and you get 5gx

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