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3 years ago

What is the 6th term of the sequence?

Mathematics

1 answer:

vesna_86 [32]3 years ago

5 0

Answer:

i really dont know maybe 6

Step-by-step explanation:

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Simplify the following expression (w^8)8

Crank

Answer:

w^64

Step-by-step explanation:

(w^8)^8

both of the powers will be multiplied; hence

w^8*8

w^64

7 0

3 years ago

Find the point on the plane 4x+3y+z=10 that is nearest to (2,0,1). What are the values of x, y, and z for the point? x= 28 /

MariettaO [177]

Answer:

$\frac{1}{\sqrt{26}}$ .

Step-by-step explanation:

The minimun distance between a point and a plane is the perpendicular distance. The formula is

d = $\frac{|Ax_0+By_0+Cz_0+D|}{\sqrt{A^{2}+B^{2}+C^{2}}}$

where $(x_0,y_0,z_0)=(2,0,1)$ , A=4, B=3, C=1 and D=-10. So, the distance is

d = $\frac{|8+1-10|}{\sqrt{16+9+1}}$

d = $\frac{|-1|}{\sqrt{26}}$

d = $\frac{1}{\sqrt{26}}$ .

4 0

3 years ago

A bag of marbles contains 3 blue, 4 green, and 3 red marbles. If you take out 2 marbles, what is the probability that they are b

tangare [24]

4/10. *. 3/9. = 12/90 = 2/15

3 0

3 years ago

A new 70-inch tv is on sale. With sales tax 5%, the cost of the tv is $3150. What is the purchase

SVETLANKA909090 [29]

$x - 0.05x = 3150 \\ 0.95x = 3150 \\ x = 3315$

4 0

3 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago