If f(x) = –x2 + 3x + 5 and g(x) = x2 + 2x, which graph shows the graph of (f + g)(x)? On a coordinate plane, a straight line wit
2 answers:
The graph of (f+g)(x) is on the coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5).
<h3>What is the graph of a parabolic equation?</h3>The graph of a parabolic equation is a curved U-shape graph from where the domain, the range, x-intercept(s), and the y-intercept(s) can be determined.
Given that:
f(x) = -x² + 3x + 5
g(x) = x² + 2x
To find (f + g)(x), we have:
(f + g)(x) = (-x² + 3x + 5)+(x² + 2x)
(f + g)(x) = -x² + 3x + 5 +x² + 2x
(f + g)(x) = 3x + 2x + 5
(f + g)(x) = 5x + 5
Use the Slope-intercept form: We are to find the graph of y = 5x + 5
y = 5x + 5
Here:
- Slope = 5
- x-intercept = (-1, 0)
- y-intercept = (0,5)
Therefore, we can conclude that on the coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5)
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Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer