All categories

3 years ago

Shawn is buying meat and chicken for a

2 answers:

5 0

If he wants a good variety of items he should purchase 2 bags or chicken for $12. Then he can spend the remaining $18 on different types of meet such as ham, turkey, sausage, or pork.

Trava [24]3 years ago

3 0

Answer:

He'll eat anything, chicken, beef, pork, he's not very choosy. He was asked how much chicken he wants to buy at different prices (each week).Step-by-step explanation:

You might be interested in

Maureen owns three bagel shops. Each shop sells 500 bagels per day. Maureen asks her store managers to use a random sample to se

Elodia [21]

Answer:

In complete questions, the completed question is in ask details

Step-by-step explanation:

Maureen has 3shops

Each sells 500bagels per day

shop A

Total bagels sample is 50 and 10 whole wheat bagels

Shop B

Total bagels sample is 100 and 23 Whole-wheat bagels

Shop C:

Total bagels sample is 25 and 7 Whole-wheat bagels.

It is noticed that the simple space of shop B is more than shop A, notice that shop B sample space is small and it can not give a reasonable valid inference.

Then, Both shop A and shop B sample space is large enough to give a reasonable valid inference

5 0

4 years ago

In rods family 3 4th of the members were glasses. Of those who do not wear glasses,1 3rd are male. What fraction of the family a

kipiarov [429]

The answer would be 1/4

7 0

3 years ago

Find the value of each variable.<br>

V125BC [204]

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = $\frac{\sqrt{3} }{2}$ , cos60° = $\frac{1}{2}$

sin45° = cos45° = $\frac{1}{\sqrt{2} }$

Using the sine ratio on the right triangle on the left

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{4\sqrt{3} }$ = $\frac{\sqrt{3} }{2}$

Cross- multiply

2a = 4 $\sqrt{3}$ × $\sqrt{3}$ = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{c}{4\sqrt{3} }$ = $\frac{1}{2}$

Cross- multiply

2c = 4 $\sqrt{3}$ ( divide both sides by 2 )

c = 2 $\sqrt{3}$

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = $\frac{a}{b}$ = $\frac{6}{b}$ = $\frac{1}{\sqrt{2} }$

Cross- multiply

b = 6 $\sqrt{2}$

cos45° = $\frac{d}{b}$ = $\frac{d}{6\sqrt{2} }$ = $\frac{1}{\sqrt{2} }$

Cross- multiply

$\sqrt{2}$ d = 6 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6 $\sqrt{2}$ , c = 2 $\sqrt{3}$ , d = 6

3 0

3 years ago

Karen set her watch 1 second behind, and it falls behind another 2 seconds every day. How many days has it been since Karen last

Kay [80]

Answer:

The equation to find the answer is $9=1+(n-1)2$ .

It has been 5 days since Karen has set her watch.

Step-by-step explanation:

Given:

Karen set her watch 1 second behind

So we will consider;

First term 'a' = 1 second

Also Given :

it falls behind another 2 seconds every day.

So we can consider;

Common difference = 2

We need to find number of days it has been 9 seconds since Karen last set her watch

Solution:

Let number of days be represented by 'n'.

Also Let $T(n) = 9$

Now By Applying formula for Arithmetic Progression we get;

$T(n)=a+(n-1)d$

Substituting the given values we get;

$9=1+(n-1)2$

Hence The equation to find the answer is $9=1+(n-1)2$ .

On Solving the above equation we get;

Subtracting both side by 1 we get;

$9-1=1+(n-1)2-1\\\\8=(n-1)2$

Now Dividing both side by 2 we get;

$\frac{8}{2}=\frac{(n-1)2}{2}\\\\4=n-1$

Adding 1 on both side we get;

$4+1=n-1+1\\\\n=5$

Hence It has been 5 days since Karen has set her watch.

3 0

4 years ago

Change 91/4 to an improper fraction.

ahrayia [7]

Answer:

91/4 (it already is an improper fraction)

Step-by-step explanation:

91/4 isn't proper as u can tell. The proper form would be 22 $\frac{3}{4}$ . So yea...

Hope this helped and have a great day!

3 0

3 years ago