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3 years ago

There are two glass 1 of them with salt solution and one with sugar solution

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

8 0

Answer:

how long question i did not found any answer

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A circular garden has a circumference of

hoa [83]

It will take him 3 hours

8 0

3 years ago

Guys help me out please and thanks :)

Jobisdone [24]

The answer is D. BC

To find an opposite of an angle, it will always be a line, not an angle.
The line that is directly opposite from the angle A is line BC.

5 0

3 years ago

Please help me right away with these problems.

viktelen [127]

Q.34

$\sum\limits_{k=1}^{\infty}420\left(1.002\right)^{k-1}$

The infinite geometric series is converges if |r| < 1.

We have r =1.002 > 1, therefore our infinite geometric series is Diverges

Answer: c. Diverges, sum not exist.

Q.35

$\sum\limits_{k=1}^{\infty}-5\left(\dfrac{4}{5}\right)^{k-1}$

The infinite geometric series is converges if |r| < 1.

We have r = 4/5 < 1, therefore our infinite geometric series is converges.

The sum S of an infinite geometric series with |r| < 1 is given by the formula :

$S=\dfrac{a_1}{1-r}$

We have:

$a_1=-5\left(\dfrac{4}{5}\right)^{1-1}=-5\left(\dfrac{4}{5}\right)^0=-5\\\\r=\dfrac{4}{5}$

substitute:

$S=\dfrac{-5}{1-\frac{4}{5}}=-\dfrac{5}{\frac{1}{5}}=-5\cdot\dfrac{5}{1}=-25$

Answer: c. Converges, -25.

4 0

3 years ago

Trigonometry question

Zigmanuir [339]

Answer:

Step-by-step explanation:

x = 87.2ft

Hope that helps :)

3 0

3 years ago

Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff

liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places. The formula for Newton's Method is

$x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }$

If our function is

$f(x)=x^5+x-6$

then the first derivative is

$f'(x)=5x^4+1$

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2. I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0

4 years ago