The function has a maximum at (1, 3).
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You know it is not a minimum because the coefficient of the squared term is negative.
You know the vertex is (1, 3) because you match the pattern to
.. y = a(x -h)^2 +k
which has its vertex at (h, k).
Graph? heidgdisdvhdhdhdvd
G in bass clef is the answer D!
Answer:
y = 5
Step-by-step explanation:
Expand the logarithm:
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You can also take the antilog first:
5y = y²
y(y -5) = 0 . . . . . subtract 5y, factor
y = 0 or 5 . . . . . y=0 is not a viable solution, so y=5.
Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)² ↔ (y-k) = a(x-h)²
This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)
Latus rectum: y-value = 15/2
Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then
Latus rectum = 5
