There were 3 friends. Each of them bought 6 packs of candy. Each pack had 18 pieces of candy. How much candy did they have in total? .
3 × 6 = 18
18 × 18 = 324
SO, they had 324 pieces of candy in total.
Hope I helped:P
The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I
The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II
Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4
Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2
From the above calculations:
x = -3/2
y = 4
Answer: Choice E) bimodal skewed
The majority of the data is towards the left side. The right outliers are skewing the mean to be pulled larger than it should be. This is why median < mean, so it's better to use the median as the measure of center. There are 2 modes here. They are the values 4 and 8 since we have these values occur the most (4 times each). That's where the term "bimodal" comes in.
Answer:
z^2 + (-1 + 5·i)·z + 14 - 7·i = 0
(1 + 2·i)^2 + (-1 + 5·i)·(1 + 2·i) + 14 - 7·i = 0
(1 + 4·i - 4) + (-1 - 2·i + 5·i - 10) + 14 - 7·i = 0
0 = 0 --> true
z^2 + (-1 + 5·i)·z + 14 - 7·i = 0
(1 - 2·i)^2 + (-1 + 5·i)·(1 - 2·i) + 14 - 7·i = 0
(1 - 4·i - 4) + (-1 + 2·i + 5·i + 10) + 14 - 7·i = 0
20 - 4·i = 0 --> false
