Answer:
32.666666666667
http://www.alcula.com/calculators/statistics/mean-absolute-deviation/
Insert data and it will calculate the (MAD).
Answer:
81 mm^2
Step-by-step explanation:
Area= 3*6*9/2=81 mm^2
This graph is a Quadratic Graph meaning it is a "U" shape. I am unable to help with the transformations since I am unaware of the signs in the problem. But I hope I helped
Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
Step-by-step explanation:
Mean = 81740
Standard deviation = 4590
Sample size = 15
Alpha level = 1-0.95 = 0.05
Df = 15-1 = 14
Critical value:
alpha/2 = 0.05/2 = 0.05
t0.025
t critical value = 2.145
Margin of error ME
2.145 x 4590/√15
2.145 x 4590/3.873
ME = 2542.09
Confidence interval
Lower CI = mean - ME
= 81740-2542.09
= 79197.91
Upper CI = mean + ME
= 81740+2542.09
= 84282.09
[ 79197.91, 84282.09]
B.
Using excel, exact answer for CI
Lower limit = 79198.142724212173
Upper limit = 84281.8572757827
C.
The assumptions to be made from the population are that
1. Samples are random
2. These samples are gotten from an approximately normal distribution
