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N76 [4]
3 years ago
15

Which types of transformations do not change the shape of a graph?

Mathematics
1 answer:
nikklg [1K]3 years ago
7 0
There are four main types of transformations: translation, rotation, reflection and dilation. These transformations fall into two categories: rigid transformations that do not change the shape or size of the preimage and non-rigid transformations that change the size but not the shape of the preimage.
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4. What is the value of the expression 72 + (33 + 12) 23 a. 3 b. 8 C. 9 d. 11​
jeyben [28]

Answer:

1107

Step-by-step explanation:

72+ (33+12)23

= 72 + (45)23

=72+ 1035

=1107

6 0
3 years ago
Sue wants to use Mental Math to find 2 x 53 write an expression she could use
Vinil7 [7]
You could separate the equation:

2*50+ 2*3=

I know that 2*50= 100; 2*3= 6

100+6= 106

I hope this helps!
~cupcake
7 0
4 years ago
What is 2.6 + 9.2 x 4 equal?
RideAnS [48]

2.6 + 9.2 x 4 would equal, <u><em>39.4</em></u>

4 0
2 years ago
Read 2 more answers
Please help and explain how to do it
nadezda [96]
So F(m) because F dollars for every mph over the speed limit
so 40 dollar speeding fine so +40 
10 dollars for every mile over and m=miles over so put them all toghether and get
F(m)=10m+40


1.
so if you were going 78 mph
to find the mph over you would do 78-70=8mph over so put in 8 for m and get
F(8)=10(8)+40=80+40=$120 fine for going at 78 mph
7 0
3 years ago
The monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be normally distribu
omeli [17]

Answer:  0.9996

Step-by-step explanation:

Given : The monthly electrical utility bills of all customers for the Far East Power and Light Company are known to be normally distributed with  a mean \mu=$\ 87.00

Standard deviation : \sigma=$\ 36.00

Sample size : n=100

Let X be the random variable that represents the electricity utility bill for a randomly selected month .

z-score : z=\dfrac{X-\mu}{\dfrac{\sigma}{\sqrt{n}}}

For X = $75.00

z=\dfrac{75.00-87.00}{\dfrac{36}{\sqrt{100}}}\approx-3.33

Now, the probability that the average bill for those sampled will exceed $75.00 will be :-

P(X>75)=P(z>-3.33)=1-P(z\leq-3.33)\\\\=1-  0.0004342=0.9995658\approx0.9996

Hence, the probability that the average bill for those sampled will exceed $75.00 =0.9996

3 0
4 years ago
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