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jonny [76]
3 years ago
6

In 2003, a remote controlled airplane became the first ever to fly nonstop across the Atlantic ocean

Mathematics
1 answer:
aniked [119]3 years ago
5 0
Sorry but you didn’t provide a question, this is a statement.
You might be interested in
Write the sentence as an inequality. The cost of a ticket t will be no more than $52.
NeX [460]

Answer:

t is less than or equal to $52, or t <= $52

Step-by-step explanation:

If you can't have more than $52, then use less than symbol (<). The sentence doesn't state that a ticket shouldn't cost $52, so it's safe to assume that you can have exactly $52.

5 0
3 years ago
Solve 3/4•1/7 in lowest terms
emmasim [6.3K]

Answer:

3/28

Step-by-step explanation:

\frac{3}{4}*\frac{1}{7}=\frac{3}{4*7}=\frac{3}{28}

that dot is a multiplication sign, right?

3 0
3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
2 years ago
Divide -5/12 and -5/8
kiruha [24]

Answer:

2/3

Step-by-step explanation:

-5/12 ÷ -5/8

Copy dot flip

-5/12 * -8/5

The 5's cancel

-8/-12

Divide the top and bottom by -4

2/3

5 0
3 years ago
Read 2 more answers
June will spin the arrow on the spinner 5 times. What is the probability that the arrow will stop on A, then B, then C, then D,
inessss [21]
Ok so assuming the board only has 4 spaces to land on (A,B,C,D) all we need to do is weight the probability, 

1/4 x 1/4 x 1/4 x 1/4 x 1/4 = 1/1024 

To solve I put the number of favorable outcomes over the number of total outcomes, in this case we had 1 favorable outcome each time and a constant of 4 possible outcomes. 
4 0
3 years ago
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