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3 years ago

The variable in -8y4 is

Mathematics

1 answer:

lesantik [10]3 years ago

8 0

Answer:

y=variable

Step-by-step explanation:

In a math expression, the variable is any letter representing for a missing number.

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For the functions f(x)=2x-6 and g(x)=5x+1 Which conposition produces the greatest output?

andrew11 [14]

(f o g)(x) = 2(5x + 1) - 6 = 10x - 4

(g o f)(x) = 5(2x - 6) + 1 = 10x - 29

So (f o g)(x) produces the greatest output.

6 0

3 years ago

As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur

Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math. It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

$y=Ce^{kt}$

Filling in our formula with the 2 conditions we are given:

$65=Ce^{10k}$ and $85=Ce^{15k}$

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k. If

$65=Ce^{10k}$ then

$\frac{65}{e^{10k}}=C$ which, by exponential rules is the same as

$C=65e^{-10k}$

Since that value of C is the same as the value of C in the other equation, we sub it in:

$85=65e^{-10k}(e^{15k})$

Divide both sides by 65 and use the rules of exponents again to get

$\frac{85}{65}=e^{-10k+15k}$ which simplifies down to

$\frac{85}{65}=e^{5k}$

Take the natural log of both sides to get

$ln(\frac{85}{65})=5k$

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

$65=Ce^{10(.0536527973)}$

which simplifies down to

$65=Ce^{.536527973}$

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

$y=38.01038064e^{(.0536527973)(23)}$ which simplifies a bit to

$y=38.01038064e^{1.234014338}$

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0

3 years ago

PLEASE HELP .!!! ILL GIVE BRAINLIEST.. *EXRTA POINTS* .. DONT SKIP :(( ! <br> ILL GIVE 40 POINTS .

RSB [31]

Answer:

x = 5

Step-by-step explanation:

11 = 4x-9

20 = 4x

20/4 = 4x/4

5 = x

5 0

3 years ago

If log10x = 3, then x =

iren [92.7K]

This is what WolframAlpha says. Look at the image below.

7 0

3 years ago

Read 2 more answers

17. Your goal is to save at least $360.00 over the next 6 weeks. How much money must you save each week in order to meet that go

OLga [1]

<h2>Answer </h2>

D. 6x>_360; x>_60

<h2>Explanation</h2>

Let $x$ be amount you will save each weeks

Since we know that you are saving over a period of 6 weeks, you will save $6x$ .

We also now that your goal is to save at least $360.00 over the period of 6 weeks, so saving more than $360.00 will be very desirable, but the goal is to save $360.00. We can rephrase this as: You need to save $360.00 or more; we can say the same using the inequality symbol $\geq$ (greater on equal than)

Now we can combine our tow parts using the inequality symbol:

$6x\geq 360$

To simplify divide both sides by 6:

$\frac{6}{6} x\geq \frac{360}{6}$

$x\geq 60$

You need to save at least $60 per week, so the correct answer is D. 6x>_360; x>_60

4 0

3 years ago