Hey man I got u. The answer for this question is B. Peace
Answer:
They are quadrilaterals that have opposite sides equal in length.
The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
You can tell how many zeros an equation has by if the equation is squared, cubed... In this equation, x^2 would have 2 zeros.
Answer: x = -7
Step-by-step explanation:
2(6 + 3x) + 1 = - 5 + 3(x - 1)
(2) (6) + (2) (3x) + 1 = -5 + (3) (x) + (3) (-1)
12 + 6x + 1 = - 5 + 3x + - 1
( 6x ) + ( 12 - 1 ) = ( 3x ) + ( -5 + -3 )
6x + 13 = 3x - 8
6x + 13 - 3x = 3x - 8 - 3x
3x + 13 = -8
3x + 13 - 13 = -8 - 13
3x = -21
3x/3 -21/3
X = -7
